eb0f0323d3
When we see a switch block which only contains one default block, emit a do {} while(false) statement instead, which is far more idiomatic and readable anyways.
20 lines
293 B
GLSL
20 lines
293 B
GLSL
#version 450
|
|
|
|
layout(location = 0) flat in int vIndex;
|
|
layout(location = 0) out vec4 FragColor;
|
|
|
|
void main()
|
|
{
|
|
do
|
|
{
|
|
if (vIndex != 1)
|
|
{
|
|
FragColor = vec4(1.0);
|
|
break;
|
|
}
|
|
FragColor = vec4(10.0);
|
|
break;
|
|
} while(false);
|
|
}
|
|
|