2012-11-02 16:53:57 +00:00
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/* wordcopy.c -- subroutines for memory copy functions. Tile version.
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2015-01-02 16:28:19 +00:00
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Copyright (C) 1991-2015 Free Software Foundation, Inc.
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2012-11-02 16:53:57 +00:00
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This file is part of the GNU C Library.
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The GNU C Library is free software; you can redistribute it and/or
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modify it under the terms of the GNU Lesser General Public
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License as published by the Free Software Foundation; either
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version 2.1 of the License, or (at your option) any later version.
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The GNU C Library is distributed in the hope that it will be useful,
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but WITHOUT ANY WARRANTY; without even the implied warranty of
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MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
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Lesser General Public License for more details.
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You should have received a copy of the GNU Lesser General Public
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License along with the GNU C Library; if not, see
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<http://www.gnu.org/licenses/>. */
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/* To optimize for tile, we make the following changes from the
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default glibc version:
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- Use the double align instruction instead of the MERGE macro.
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- Since we don't have offset addressing mode, make sure the loads /
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stores in the inner loop always have indices of 0.
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- Use post-increment addresses in the inner loops, which yields
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better scheduling. */
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/* BE VERY CAREFUL IF YOU CHANGE THIS CODE...! */
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#include <stddef.h>
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#include <memcopy.h>
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/* Provide the appropriate dblalign builtin to shift two registers
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based on the alignment of a pointer held in a third register. */
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#ifdef __tilegx__
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#define DBLALIGN __insn_dblalign
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#else
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#define DBLALIGN __insn_dword_align
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#endif
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/* _wordcopy_fwd_aligned -- Copy block beginning at SRCP to
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block beginning at DSTP with LEN `op_t' words (not LEN bytes!).
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Both SRCP and DSTP should be aligned for memory operations on `op_t's. */
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void
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_wordcopy_fwd_aligned (dstp, srcp, len)
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long int dstp;
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long int srcp;
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size_t len;
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{
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op_t a0, a1;
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switch (len % 8)
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{
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case 2:
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a0 = ((op_t *) srcp)[0];
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srcp += OPSIZ;
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len += 6;
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goto do1;
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case 3:
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a1 = ((op_t *) srcp)[0];
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srcp += OPSIZ;
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len += 5;
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goto do2;
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case 4:
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a0 = ((op_t *) srcp)[0];
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srcp += OPSIZ;
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len += 4;
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goto do3;
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case 5:
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a1 = ((op_t *) srcp)[0];
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srcp += OPSIZ;
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len += 3;
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goto do4;
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case 6:
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a0 = ((op_t *) srcp)[0];
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srcp += OPSIZ;
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len += 2;
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goto do5;
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case 7:
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a1 = ((op_t *) srcp)[0];
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srcp += OPSIZ;
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len += 1;
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goto do6;
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case 0:
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if (OP_T_THRES <= 3 * OPSIZ && len == 0)
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return;
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a0 = ((op_t *) srcp)[0];
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srcp += OPSIZ;
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goto do7;
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case 1:
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a1 = ((op_t *) srcp)[0];
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srcp += OPSIZ;
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len -= 1;
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if (OP_T_THRES <= 3 * OPSIZ && len == 0)
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goto do0;
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goto do8; /* No-op. */
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}
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do
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{
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do8:
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a0 = ((op_t *) srcp)[0];
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((op_t *) dstp)[0] = a1;
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srcp += OPSIZ;
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dstp += OPSIZ;
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do7:
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a1 = ((op_t *) srcp)[0];
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((op_t *) dstp)[0] = a0;
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srcp += OPSIZ;
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dstp += OPSIZ;
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do6:
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a0 = ((op_t *) srcp)[0];
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((op_t *) dstp)[0] = a1;
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srcp += OPSIZ;
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dstp += OPSIZ;
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do5:
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a1 = ((op_t *) srcp)[0];
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((op_t *) dstp)[0] = a0;
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srcp += OPSIZ;
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dstp += OPSIZ;
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do4:
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a0 = ((op_t *) srcp)[0];
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((op_t *) dstp)[0] = a1;
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srcp += OPSIZ;
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dstp += OPSIZ;
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do3:
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a1 = ((op_t *) srcp)[0];
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((op_t *) dstp)[0] = a0;
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srcp += OPSIZ;
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dstp += OPSIZ;
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do2:
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a0 = ((op_t *) srcp)[0];
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((op_t *) dstp)[0] = a1;
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srcp += OPSIZ;
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dstp += OPSIZ;
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do1:
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a1 = ((op_t *) srcp)[0];
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((op_t *) dstp)[0] = a0;
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srcp += OPSIZ;
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dstp += OPSIZ;
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len -= 8;
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}
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while (len != 0);
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/* This is the right position for do0. Please don't move
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it into the loop. */
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do0:
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((op_t *) dstp)[0] = a1;
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}
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/* _wordcopy_fwd_dest_aligned -- Copy block beginning at SRCP to
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block beginning at DSTP with LEN `op_t' words (not LEN bytes!).
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DSTP should be aligned for memory operations on `op_t's, but SRCP must
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*not* be aligned. */
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void
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_wordcopy_fwd_dest_aligned (dstp, srcp, len)
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long int dstp;
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long int srcp;
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size_t len;
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{
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void * srci;
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op_t a0, a1, a2, a3;
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/* Save the initial source pointer so we know the number of bytes to
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shift for merging two unaligned results. */
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srci = (void *) srcp;
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/* Make SRCP aligned by rounding it down to the beginning of the `op_t'
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it points in the middle of. */
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srcp &= -OPSIZ;
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switch (len % 4)
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{
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case 2:
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a1 = ((op_t *) srcp)[0];
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a2 = ((op_t *) srcp)[1];
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len += 2;
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srcp += 2 * OPSIZ;
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goto do1;
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case 3:
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a0 = ((op_t *) srcp)[0];
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a1 = ((op_t *) srcp)[1];
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len += 1;
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srcp += 2 * OPSIZ;
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goto do2;
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case 0:
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if (OP_T_THRES <= 3 * OPSIZ && len == 0)
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return;
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a3 = ((op_t *) srcp)[0];
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a0 = ((op_t *) srcp)[1];
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len += 0;
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srcp += 2 * OPSIZ;
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goto do3;
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case 1:
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a2 = ((op_t *) srcp)[0];
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a3 = ((op_t *) srcp)[1];
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srcp += 2 * OPSIZ;
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len -= 1;
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if (OP_T_THRES <= 3 * OPSIZ && len == 0)
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goto do0;
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goto do4; /* No-op. */
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}
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do
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{
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do4:
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a0 = ((op_t *) srcp)[0];
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a2 = DBLALIGN (a2, a3, srci);
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((op_t *) dstp)[0] = a2;
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srcp += OPSIZ;
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dstp += OPSIZ;
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do3:
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a1 = ((op_t *) srcp)[0];
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a3 = DBLALIGN (a3, a0, srci);
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((op_t *) dstp)[0] = a3;
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srcp += OPSIZ;
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dstp += OPSIZ;
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do2:
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a2 = ((op_t *) srcp)[0];
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a0 = DBLALIGN (a0, a1, srci);
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((op_t *) dstp)[0] = a0;
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srcp += OPSIZ;
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dstp += OPSIZ;
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do1:
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a3 = ((op_t *) srcp)[0];
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a1 = DBLALIGN (a1, a2, srci);
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((op_t *) dstp)[0] = a1;
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srcp += OPSIZ;
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dstp += OPSIZ;
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len -= 4;
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}
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while (len != 0);
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/* This is the right position for do0. Please don't move
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it into the loop. */
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do0:
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((op_t *) dstp)[0] = DBLALIGN (a2, a3, srci);
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}
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/* _wordcopy_bwd_aligned -- Copy block finishing right before
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SRCP to block finishing right before DSTP with LEN `op_t' words
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(not LEN bytes!). Both SRCP and DSTP should be aligned for memory
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operations on `op_t's. */
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void
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_wordcopy_bwd_aligned (dstp, srcp, len)
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long int dstp;
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long int srcp;
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size_t len;
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{
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op_t a0, a1;
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long int srcp1;
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srcp1 = srcp - 1 * OPSIZ;
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srcp -= 2 * OPSIZ;
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dstp -= 1 * OPSIZ;
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switch (len % 8)
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{
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case 2:
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a0 = ((op_t *) srcp1)[0];
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len += 6;
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goto do1;
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case 3:
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a1 = ((op_t *) srcp1)[0];
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len += 5;
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goto do2;
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case 4:
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a0 = ((op_t *) srcp1)[0];
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len += 4;
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goto do3;
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case 5:
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a1 = ((op_t *) srcp1)[0];
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len += 3;
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goto do4;
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case 6:
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a0 = ((op_t *) srcp1)[0];
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len += 2;
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goto do5;
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case 7:
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a1 = ((op_t *) srcp1)[0];
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len += 1;
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goto do6;
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case 0:
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if (OP_T_THRES <= 3 * OPSIZ && len == 0)
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return;
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a0 = ((op_t *) srcp1)[0];
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goto do7;
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case 1:
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a1 = ((op_t *) srcp1)[0];
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len -= 1;
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if (OP_T_THRES <= 3 * OPSIZ && len == 0)
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goto do0;
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goto do8; /* No-op. */
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}
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do
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{
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do8:
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a0 = ((op_t *) srcp)[0];
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((op_t *) dstp)[0] = a1;
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srcp -= OPSIZ;
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dstp -= OPSIZ;
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do7:
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a1 = ((op_t *) srcp)[0];
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((op_t *) dstp)[0] = a0;
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srcp -= OPSIZ;
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dstp -= OPSIZ;
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do6:
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a0 = ((op_t *) srcp)[0];
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((op_t *) dstp)[0] = a1;
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srcp -= OPSIZ;
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dstp -= OPSIZ;
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do5:
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a1 = ((op_t *) srcp)[0];
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((op_t *) dstp)[0] = a0;
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srcp -= OPSIZ;
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dstp -= OPSIZ;
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do4:
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a0 = ((op_t *) srcp)[0];
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((op_t *) dstp)[0] = a1;
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srcp -= OPSIZ;
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dstp -= OPSIZ;
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do3:
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a1 = ((op_t *) srcp)[0];
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((op_t *) dstp)[0] = a0;
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srcp -= OPSIZ;
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dstp -= OPSIZ;
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do2:
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a0 = ((op_t *) srcp)[0];
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((op_t *) dstp)[0] = a1;
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srcp -= OPSIZ;
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dstp -= OPSIZ;
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do1:
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a1 = ((op_t *) srcp)[0];
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((op_t *) dstp)[0] = a0;
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srcp -= OPSIZ;
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dstp -= OPSIZ;
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len -= 8;
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}
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|
while (len != 0);
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|
|
|
|
|
|
|
/* This is the right position for do0. Please don't move
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|
|
|
it into the loop. */
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|
|
do0:
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((op_t *) dstp)[0] = a1;
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}
|
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|
|
|
|
|
|
/* _wordcopy_bwd_dest_aligned -- Copy block finishing right
|
|
|
|
before SRCP to block finishing right before DSTP with LEN `op_t'
|
|
|
|
words (not LEN bytes!). DSTP should be aligned for memory
|
|
|
|
operations on `op_t', but SRCP must *not* be aligned. */
|
|
|
|
|
|
|
|
void
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|
|
|
_wordcopy_bwd_dest_aligned (dstp, srcp, len)
|
|
|
|
long int dstp;
|
|
|
|
long int srcp;
|
|
|
|
size_t len;
|
|
|
|
{
|
|
|
|
void * srci;
|
|
|
|
op_t a0, a1, a2, a3;
|
|
|
|
op_t b0, b1, b2, b3;
|
|
|
|
|
|
|
|
/* Save the initial source pointer so we know the number of bytes to
|
|
|
|
shift for merging two unaligned results. */
|
|
|
|
srci = (void *) srcp;
|
|
|
|
|
|
|
|
/* Make SRCP aligned by rounding it down to the beginning of the op_t
|
|
|
|
it points in the middle of. */
|
|
|
|
srcp &= -OPSIZ;
|
|
|
|
srcp += OPSIZ;
|
|
|
|
|
|
|
|
switch (len % 4)
|
|
|
|
{
|
|
|
|
case 2:
|
|
|
|
srcp -= 3 * OPSIZ;
|
|
|
|
dstp -= 1 * OPSIZ;
|
|
|
|
b2 = ((op_t *) srcp)[2];
|
|
|
|
b1 = a1 = ((op_t *) srcp)[1];
|
|
|
|
len += 2;
|
|
|
|
goto do1;
|
|
|
|
case 3:
|
|
|
|
srcp -= 3 * OPSIZ;
|
|
|
|
dstp -= 1 * OPSIZ;
|
|
|
|
b3 = ((op_t *) srcp)[2];
|
|
|
|
b2 = a2 = ((op_t *) srcp)[1];
|
|
|
|
len += 1;
|
|
|
|
goto do2;
|
|
|
|
case 0:
|
|
|
|
if (OP_T_THRES <= 3 * OPSIZ && len == 0)
|
|
|
|
return;
|
|
|
|
srcp -= 3 * OPSIZ;
|
|
|
|
dstp -= 1 * OPSIZ;
|
|
|
|
b0 = ((op_t *) srcp)[2];
|
|
|
|
b3 = a3 = ((op_t *) srcp)[1];
|
|
|
|
goto do3;
|
|
|
|
case 1:
|
|
|
|
srcp -= 3 * OPSIZ;
|
|
|
|
dstp -= 1 * OPSIZ;
|
|
|
|
b1 = ((op_t *) srcp)[2];
|
|
|
|
b0 = a0 = ((op_t *) srcp)[1];
|
|
|
|
len -= 1;
|
|
|
|
if (OP_T_THRES <= 3 * OPSIZ && len == 0)
|
|
|
|
goto do0;
|
|
|
|
goto do4; /* No-op. */
|
|
|
|
}
|
|
|
|
|
|
|
|
do
|
|
|
|
{
|
|
|
|
do4:
|
|
|
|
b3 = a3 = ((op_t *) srcp)[0];
|
|
|
|
a0 = DBLALIGN (a0, b1, srci);
|
|
|
|
((op_t *) dstp)[0] = a0;
|
|
|
|
srcp -= OPSIZ;
|
|
|
|
dstp -= OPSIZ;
|
|
|
|
do3:
|
|
|
|
b2 = a2 = ((op_t *) srcp)[0];
|
|
|
|
a3 = DBLALIGN (a3, b0, srci);
|
|
|
|
((op_t *) dstp)[0] = a3;
|
|
|
|
srcp -= OPSIZ;
|
|
|
|
dstp -= OPSIZ;
|
|
|
|
do2:
|
|
|
|
b1 = a1 = ((op_t *) srcp)[0];
|
|
|
|
a2 = DBLALIGN (a2, b3, srci);
|
|
|
|
((op_t *) dstp)[0] = a2;
|
|
|
|
srcp -= OPSIZ;
|
|
|
|
dstp -= OPSIZ;
|
|
|
|
do1:
|
|
|
|
b0 = a0 = ((op_t *) srcp)[0];
|
|
|
|
a1 = DBLALIGN (a1, b2, srci);
|
|
|
|
((op_t *) dstp)[0] = a1;
|
|
|
|
srcp -= OPSIZ;
|
|
|
|
dstp -= OPSIZ;
|
|
|
|
|
|
|
|
len -= 4;
|
|
|
|
}
|
|
|
|
while (len != 0);
|
|
|
|
|
|
|
|
/* This is the right position for do0. Please don't move
|
|
|
|
it into the loop. */
|
|
|
|
do0:
|
|
|
|
a0 = DBLALIGN (a0, b1, srci);
|
|
|
|
((op_t *) dstp)[0] = a0;
|
|
|
|
}
|