1999-07-29 20:36:56 +00:00
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#include <stdio.h>
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#include <stdlib.h>
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#define VAR "FOOBAR"
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char putenv_val[100] = VAR "=some longer value";
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int
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main (void)
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{
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int result = 0;
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const char *valp;
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/* First test: remove entry FOOBAR, whether it exists or not. */
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unsetenv (VAR);
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/* Now getting the value should fail. */
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if (getenv (VAR) != NULL)
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{
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printf ("There should be no `%s' value\n", VAR);
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result = 1;
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}
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/* Now add a value, with the replace flag cleared. */
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if (setenv (VAR, "one", 0) != 0)
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{
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printf ("setenv #1 failed: %m\n");
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result = 1;
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}
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/* Getting this value should now be possible. */
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valp = getenv (VAR);
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if (valp == NULL || strcmp (valp, "one") != 0)
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{
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puts ("getenv #2 failed");
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result = 1;
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}
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/* Try to replace without the replace flag set. This should fail. */
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if (setenv (VAR, "two", 0) != 0)
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{
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printf ("setenv #2 failed: %m\n");
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result = 1;
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}
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/* The value shouldn't have changed. */
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valp = getenv (VAR);
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if (valp == NULL || strcmp (valp, "one") != 0)
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{
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puts ("getenv #3 failed");
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result = 1;
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}
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/* Now replace the value using putenv. */
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if (putenv (putenv_val) != 0)
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{
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printf ("putenv #1 failed: %m\n");
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result = 1;
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}
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/* The value should have changed now. */
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valp = getenv (VAR);
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if (valp == NULL || strcmp (valp, "some longer value") != 0)
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{
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printf ("getenv #4 failed (is \"%s\")\n", valp);
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result = 1;
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}
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/* Now one tricky check: changing the variable passed in putenv should
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change the environment. */
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strcpy (&putenv_val[sizeof VAR], "a short one");
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/* The value should have changed again. */
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valp = getenv (VAR);
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if (valp == NULL || strcmp (valp, "a short one") != 0)
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{
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puts ("getenv #5 failed");
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result = 1;
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}
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/* It should even be possible to rename the variable. */
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strcpy (putenv_val, "XYZZY=some other value");
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/* Now a lookup using the old name should fail. */
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if (getenv (VAR) != NULL)
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{
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puts ("getenv #6 failed");
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result = 1;
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}
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/* But using the new name it should work. */
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valp = getenv ("XYZZY");
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if (valp == NULL || strcmp (valp, "some other value") != 0)
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{
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puts ("getenv #7 failed");
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result = 1;
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}
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/* Create a new variable with the old name. */
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if (setenv (VAR, "a new value", 0) != 0)
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{
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printf ("setenv #3 failed: %m\n");
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result = 1;
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}
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/* At this point a getenv call must return the new value. */
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valp = getenv (VAR);
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if (valp == NULL || strcmp (valp, "a new value") != 0)
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{
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puts ("getenv #8 failed");
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result = 1;
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}
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/* Black magic: rename the variable we added using putenv back. */
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strcpy (putenv_val, VAR "=old name new value");
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/* This is interesting. We have two variables with the same name.
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Getting a value should return one of them. */
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valp = getenv (VAR);
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if (valp == NULL
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|| (strcmp (valp, "a new value") != 0
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&& strcmp (valp, "old name new value") != 0))
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{
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puts ("getenv #9 failed");
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result = 1;
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}
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/* More fun ahead: we are now removing the variable. This should remove
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1999-08-30 20:15:06 +00:00
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both values. The cast is ok: this call should never put the string
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in the environment and it should never modify it. */
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putenv ((char *) VAR);
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1999-07-29 20:36:56 +00:00
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/* Getting the value should now fail. */
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if (getenv (VAR) != NULL)
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{
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printf ("getenv #10 failed (\"%s\" found)\n", getenv (VAR));
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result = 1;
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}
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1999-09-20 02:18:14 +00:00
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/* Now a test with an environment variable that's one character long.
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This is to test a special case in the getenv implementation. */
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strcpy (putenv_val, "X=one character test");
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if (putenv (putenv_val) != 0)
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{
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printf ("putenv #2 failed: %m\n");
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result = 1;
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}
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valp = getenv ("X");
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if (valp == NULL || strcmp (valp, "one character test") != 0)
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{
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puts ("getenv #11 failed");
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result = 1;
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}
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1999-07-29 20:36:56 +00:00
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return result;
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}
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