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Fix LIBC_PROG_BINUTILS for -fuse-ld=lld

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GCC does not print the correct linker when -fuse-ld=lld is used with
the -print-prog-name=ld:

  $ gcc -v 2>&1 | tail -n 1
  gcc version 11.2.0 (Ubuntu 11.2.0-7ubuntu2)
  $ gcc
  ld

This is different than for gold:

  $ gcc -fuse-ld=gold -print-prog-name=ld
  ld.gold

Using ld.lld as the static linker name prints the expected result.

This is only required when -fuse-ld=lld is used, if lld is used as
the 'ld' programs (through a symlink) LIBC_PROG_BINUTILS works
as expected.

Checked on x86_64-linux-gnu.

Reviewed-by: Fangrui Song <maskray@google.com>
This commit is contained in:
Adhemerval Zanella 2021-10-26 09:02:57 -03:00
parent 66a273d16a
commit 3d5ecb6246
2 changed files with 10 additions and 2 deletions
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6
aclocal.m4 vendored
View File

@ -114,8 +114,12 @@ if test -n "$path_binutils"; then
path_binutils=`(cd $path_binutils; pwd) | sed 's%/*$%/%'`
CC="$CC -B$path_binutils"
fi
case "$CC" in
*fuse-ld=lld*) LDNAME=ld.lld;;
*) LDNAME=ld;;
esac
AS=`$CC -print-prog-name=as`
LD=`$CC -print-prog-name=ld`
LD=`$CC -print-prog-name=$LDNAME`
AR=`$CC -print-prog-name=ar`
AC_SUBST(AR)
OBJDUMP=`$CC -print-prog-name=objdump`

6
configure vendored
View File

@ -4549,8 +4549,12 @@ if test -n "$path_binutils"; then
path_binutils=`(cd $path_binutils; pwd) | sed 's%/*$%/%'`
CC="$CC -B$path_binutils"
fi
case "$CC" in
*fuse-ld=lld*) LDNAME=ld.lld;;
*) LDNAME=ld;;
esac
AS=`$CC -print-prog-name=as`
LD=`$CC -print-prog-name=ld`
LD=`$CC -print-prog-name=$LDNAME`
AR=`$CC -print-prog-name=ar`
OBJDUMP=`$CC -print-prog-name=objdump`