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169 lines
4.7 KiB
C
169 lines
4.7 KiB
C
/* expm1l.c
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*
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* Exponential function, minus 1
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* 128-bit long double precision
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*
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*
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*
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* SYNOPSIS:
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*
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* long double x, y, expm1l();
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*
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* y = expm1l( x );
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*
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*
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*
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* DESCRIPTION:
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*
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* Returns e (2.71828...) raised to the x power, minus one.
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*
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* Range reduction is accomplished by separating the argument
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* into an integer k and fraction f such that
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*
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* x k f
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* e = 2 e.
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*
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* An expansion x + .5 x^2 + x^3 R(x) approximates exp(f) - 1
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* in the basic range [-0.5 ln 2, 0.5 ln 2].
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*
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*
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* ACCURACY:
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*
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* Relative error:
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* arithmetic domain # trials peak rms
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* IEEE -79,+MAXLOG 100,000 1.7e-34 4.5e-35
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*
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*/
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/* Copyright 2001 by Stephen L. Moshier
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This library is free software; you can redistribute it and/or
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modify it under the terms of the GNU Lesser General Public
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License as published by the Free Software Foundation; either
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version 2.1 of the License, or (at your option) any later version.
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This library is distributed in the hope that it will be useful,
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but WITHOUT ANY WARRANTY; without even the implied warranty of
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MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
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Lesser General Public License for more details.
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You should have received a copy of the GNU Lesser General Public
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License along with this library; if not, see
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<https://www.gnu.org/licenses/>. */
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#include <errno.h>
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#include <float.h>
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#include <math.h>
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#include <math_private.h>
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#include <math-underflow.h>
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#include <libm-alias-ldouble.h>
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/* exp(x) - 1 = x + 0.5 x^2 + x^3 P(x)/Q(x)
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-.5 ln 2 < x < .5 ln 2
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Theoretical peak relative error = 8.1e-36 */
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static const _Float128
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P0 = L(2.943520915569954073888921213330863757240E8),
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P1 = L(-5.722847283900608941516165725053359168840E7),
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P2 = L(8.944630806357575461578107295909719817253E6),
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P3 = L(-7.212432713558031519943281748462837065308E5),
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P4 = L(4.578962475841642634225390068461943438441E4),
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P5 = L(-1.716772506388927649032068540558788106762E3),
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P6 = L(4.401308817383362136048032038528753151144E1),
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P7 = L(-4.888737542888633647784737721812546636240E-1),
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Q0 = L(1.766112549341972444333352727998584753865E9),
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Q1 = L(-7.848989743695296475743081255027098295771E8),
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Q2 = L(1.615869009634292424463780387327037251069E8),
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Q3 = L(-2.019684072836541751428967854947019415698E7),
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Q4 = L(1.682912729190313538934190635536631941751E6),
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Q5 = L(-9.615511549171441430850103489315371768998E4),
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Q6 = L(3.697714952261803935521187272204485251835E3),
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Q7 = L(-8.802340681794263968892934703309274564037E1),
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/* Q8 = 1.000000000000000000000000000000000000000E0 */
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/* C1 + C2 = ln 2 */
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C1 = L(6.93145751953125E-1),
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C2 = L(1.428606820309417232121458176568075500134E-6),
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/* ln 2^-114 */
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minarg = L(-7.9018778583833765273564461846232128760607E1), big = L(1e4932);
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_Float128
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__expm1l (_Float128 x)
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{
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_Float128 px, qx, xx;
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int32_t ix, sign;
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ieee854_long_double_shape_type u;
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int k;
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/* Detect infinity and NaN. */
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u.value = x;
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ix = u.parts32.w0;
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sign = ix & 0x80000000;
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ix &= 0x7fffffff;
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if (!sign && ix >= 0x40060000)
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{
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/* If num is positive and exp >= 6 use plain exp. */
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return __expl (x);
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}
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if (ix >= 0x7fff0000)
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{
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/* Infinity (which must be negative infinity). */
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if (((ix & 0xffff) | u.parts32.w1 | u.parts32.w2 | u.parts32.w3) == 0)
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return -1;
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/* NaN. Invalid exception if signaling. */
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return x + x;
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}
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/* expm1(+- 0) = +- 0. */
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if ((ix == 0) && (u.parts32.w1 | u.parts32.w2 | u.parts32.w3) == 0)
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return x;
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/* Minimum value. */
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if (x < minarg)
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return (4.0/big - 1);
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/* Avoid internal underflow when result does not underflow, while
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ensuring underflow (without returning a zero of the wrong sign)
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when the result does underflow. */
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if (fabsl (x) < L(0x1p-113))
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{
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math_check_force_underflow (x);
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return x;
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}
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/* Express x = ln 2 (k + remainder), remainder not exceeding 1/2. */
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xx = C1 + C2; /* ln 2. */
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px = floorl (0.5 + x / xx);
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k = px;
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/* remainder times ln 2 */
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x -= px * C1;
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x -= px * C2;
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/* Approximate exp(remainder ln 2). */
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px = (((((((P7 * x
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+ P6) * x
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+ P5) * x + P4) * x + P3) * x + P2) * x + P1) * x + P0) * x;
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qx = (((((((x
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+ Q7) * x
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+ Q6) * x + Q5) * x + Q4) * x + Q3) * x + Q2) * x + Q1) * x + Q0;
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xx = x * x;
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qx = x + (0.5 * xx + xx * px / qx);
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/* exp(x) = exp(k ln 2) exp(remainder ln 2) = 2^k exp(remainder ln 2).
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We have qx = exp(remainder ln 2) - 1, so
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exp(x) - 1 = 2^k (qx + 1) - 1
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= 2^k qx + 2^k - 1. */
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px = __ldexpl (1, k);
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x = px * qx + (px - 1.0);
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return x;
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}
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libm_hidden_def (__expm1l)
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libm_alias_ldouble (__expm1, expm1)
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