mirror of
https://sourceware.org/git/glibc.git
synced 2024-12-27 13:10:29 +00:00
58 lines
2.1 KiB
C
58 lines
2.1 KiB
C
/* `long long int' divison with remainder.
|
|
Copyright (C) 1992, 1996, 1997 Free Software Foundation, Inc.
|
|
This file is part of the GNU C Library.
|
|
|
|
The GNU C Library is free software; you can redistribute it and/or
|
|
modify it under the terms of the GNU Lesser General Public
|
|
License as published by the Free Software Foundation; either
|
|
version 2.1 of the License, or (at your option) any later version.
|
|
|
|
The GNU C Library is distributed in the hope that it will be useful,
|
|
but WITHOUT ANY WARRANTY; without even the implied warranty of
|
|
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
|
|
Lesser General Public License for more details.
|
|
|
|
You should have received a copy of the GNU Lesser General Public
|
|
License along with the GNU C Library; if not, write to the Free
|
|
Software Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA
|
|
02111-1307 USA. */
|
|
|
|
#include <stdlib.h>
|
|
|
|
|
|
/* Return the `lldiv_t' representation of NUMER over DENOM. */
|
|
lldiv_t
|
|
lldiv (numer, denom)
|
|
long long int numer;
|
|
long long int denom;
|
|
{
|
|
lldiv_t result;
|
|
|
|
result.quot = numer / denom;
|
|
result.rem = numer % denom;
|
|
|
|
/* The ANSI standard says that |QUOT| <= |NUMER / DENOM|, where
|
|
NUMER / DENOM is to be computed in infinite precision. In
|
|
other words, we should always truncate the quotient towards
|
|
zero, never -infinity. Machine division and remainer may
|
|
work either way when one or both of NUMER or DENOM is
|
|
negative. If only one is negative and QUOT has been
|
|
truncated towards -infinity, REM will have the same sign as
|
|
DENOM and the opposite sign of NUMER; if both are negative
|
|
and QUOT has been truncated towards -infinity, REM will be
|
|
positive (will have the opposite sign of NUMER). These are
|
|
considered `wrong'. If both are NUM and DENOM are positive,
|
|
RESULT will always be positive. This all boils down to: if
|
|
NUMER >= 0, but REM < 0, we got the wrong answer. In that
|
|
case, to get the right answer, add 1 to QUOT and subtract
|
|
DENOM from REM. */
|
|
|
|
if (numer >= 0 && result.rem < 0)
|
|
{
|
|
++result.quot;
|
|
result.rem -= denom;
|
|
}
|
|
|
|
return result;
|
|
}
|