mirror of
https://sourceware.org/git/glibc.git
synced 2024-11-27 07:20:11 +00:00
130 lines
3.8 KiB
C
130 lines
3.8 KiB
C
/* Compute x^2 + y^2 - 1, without large cancellation error.
|
|
Copyright (C) 2012-2013 Free Software Foundation, Inc.
|
|
This file is part of the GNU C Library.
|
|
|
|
The GNU C Library is free software; you can redistribute it and/or
|
|
modify it under the terms of the GNU Lesser General Public
|
|
License as published by the Free Software Foundation; either
|
|
version 2.1 of the License, or (at your option) any later version.
|
|
|
|
The GNU C Library is distributed in the hope that it will be useful,
|
|
but WITHOUT ANY WARRANTY; without even the implied warranty of
|
|
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
|
|
Lesser General Public License for more details.
|
|
|
|
You should have received a copy of the GNU Lesser General Public
|
|
License along with the GNU C Library; if not, see
|
|
<http://www.gnu.org/licenses/>. */
|
|
|
|
#include <math.h>
|
|
#include <math_private.h>
|
|
#include <float.h>
|
|
#include <stdlib.h>
|
|
|
|
/* Calculate X + Y exactly and store the result in *HI + *LO. It is
|
|
given that |X| >= |Y| and the values are small enough that no
|
|
overflow occurs. */
|
|
|
|
static inline void
|
|
add_split (double *hi, double *lo, double x, double y)
|
|
{
|
|
/* Apply Dekker's algorithm. */
|
|
*hi = x + y;
|
|
*lo = (x - *hi) + y;
|
|
}
|
|
|
|
/* Calculate X * Y exactly and store the result in *HI + *LO. It is
|
|
given that the values are small enough that no overflow occurs and
|
|
large enough (or zero) that no underflow occurs. */
|
|
|
|
static inline void
|
|
mul_split (double *hi, double *lo, double x, double y)
|
|
{
|
|
#ifdef __FP_FAST_FMA
|
|
/* Fast built-in fused multiply-add. */
|
|
*hi = x * y;
|
|
*lo = __builtin_fma (x, y, -*hi);
|
|
#elif defined FP_FAST_FMA
|
|
/* Fast library fused multiply-add, compiler before GCC 4.6. */
|
|
*hi = x * y;
|
|
*lo = __fma (x, y, -*hi);
|
|
#else
|
|
/* Apply Dekker's algorithm. */
|
|
*hi = x * y;
|
|
# define C ((1 << (DBL_MANT_DIG + 1) / 2) + 1)
|
|
double x1 = x * C;
|
|
double y1 = y * C;
|
|
# undef C
|
|
x1 = (x - x1) + x1;
|
|
y1 = (y - y1) + y1;
|
|
double x2 = x - x1;
|
|
double y2 = y - y1;
|
|
*lo = (((x1 * y1 - *hi) + x1 * y2) + x2 * y1) + x2 * y2;
|
|
#endif
|
|
}
|
|
|
|
/* Compare absolute values of floating-point values pointed to by P
|
|
and Q for qsort. */
|
|
|
|
static int
|
|
compare (const void *p, const void *q)
|
|
{
|
|
double pd = fabs (*(const double *) p);
|
|
double qd = fabs (*(const double *) q);
|
|
if (pd < qd)
|
|
return -1;
|
|
else if (pd == qd)
|
|
return 0;
|
|
else
|
|
return 1;
|
|
}
|
|
|
|
/* Return X^2 + Y^2 - 1, computed without large cancellation error.
|
|
It is given that 1 > X >= Y >= epsilon / 2, and that either X >=
|
|
0.75 or Y >= 0.5. */
|
|
|
|
long double
|
|
__x2y2m1l (long double x, long double y)
|
|
{
|
|
double vals[12];
|
|
SET_RESTORE_ROUND (FE_TONEAREST);
|
|
union ibm_extended_long_double xu, yu;
|
|
xu.d = x;
|
|
yu.d = y;
|
|
if (fabs (xu.dd[1]) < 0x1p-500)
|
|
xu.dd[1] = 0.0;
|
|
if (fabs (yu.dd[1]) < 0x1p-500)
|
|
yu.dd[1] = 0.0;
|
|
mul_split (&vals[1], &vals[0], xu.dd[0], xu.dd[0]);
|
|
mul_split (&vals[3], &vals[2], xu.dd[0], xu.dd[1]);
|
|
vals[2] *= 2.0;
|
|
vals[3] *= 2.0;
|
|
mul_split (&vals[5], &vals[4], xu.dd[1], xu.dd[1]);
|
|
mul_split (&vals[7], &vals[6], yu.dd[0], yu.dd[0]);
|
|
mul_split (&vals[9], &vals[8], yu.dd[0], yu.dd[1]);
|
|
vals[8] *= 2.0;
|
|
vals[9] *= 2.0;
|
|
mul_split (&vals[11], &vals[10], yu.dd[1], yu.dd[1]);
|
|
if (xu.dd[0] >= 0.75)
|
|
vals[1] -= 1.0;
|
|
else
|
|
{
|
|
vals[1] -= 0.5;
|
|
vals[7] -= 0.5;
|
|
}
|
|
qsort (vals, 12, sizeof (double), compare);
|
|
/* Add up the values so that each element of VALS has absolute value
|
|
at most equal to the last set bit of the next nonzero
|
|
element. */
|
|
for (size_t i = 0; i <= 10; i++)
|
|
{
|
|
add_split (&vals[i + 1], &vals[i], vals[i + 1], vals[i]);
|
|
qsort (vals + i + 1, 11 - i, sizeof (double), compare);
|
|
}
|
|
/* Now any error from this addition will be small. */
|
|
long double retval = (long double) vals[11];
|
|
for (size_t i = 10; i != (size_t) -1; i--)
|
|
retval += (long double) vals[i];
|
|
return retval;
|
|
}
|