glibc/sysdeps/ieee754/ldbl-96/s_scalblnl.c
Joseph Myers 5a9e4c09a2 Fix ldbl-96 scalblnl underflowing results (bug 17803).
The ldbl-96 implementation of scalblnl (used for x86_64 and ia64) uses
a condition k <= -63 to determine when a standard underflowing result
tiny*__copysignl(tiny,x) should be returned.  However, that condition
corresponds to values with exponent -16446 or less, and in the case of
-16446, the correct result for round-to-nearest depends on whether the
value is exactly 0x1p-16446 (half the least subnormal) or more than
that.  This patch fixes the bug by changing the condition to k <= -64
and accordingly adjusting the exponent by 64 not 63 when converting to
a normal value.

Tested for x86_64.

	[BZ #17803]
	* sysdeps/ieee754/ldbl-96/s_scalblnl.c (twom63): Rename to
	twom64.  Adjust value to 0x1p-64L.
	(__scalblnl): Only return standard underflowing result for K <=
	-64 not K <= -63; adjust exponent for underflowing result by 64
	not 63.
	* math/libm-test.inc (scalbn_test_data): Add more tests.
	(scalbln_test_data): Likewise.
2015-01-12 23:02:14 +00:00

61 lines
1.8 KiB
C

/* s_scalbnl.c -- long double version of s_scalbn.c.
* Conversion to long double by Ulrich Drepper,
* Cygnus Support, drepper@cygnus.com.
*/
/*
* ====================================================
* Copyright (C) 1993 by Sun Microsystems, Inc. All rights reserved.
*
* Developed at SunPro, a Sun Microsystems, Inc. business.
* Permission to use, copy, modify, and distribute this
* software is freely granted, provided that this notice
* is preserved.
* ====================================================
*/
/*
* scalbnl (long double x, int n)
* scalbnl(x,n) returns x* 2**n computed by exponent
* manipulation rather than by actually performing an
* exponentiation or a multiplication.
*/
#include <math.h>
#include <math_private.h>
static const long double
two63 = 0x1p63L,
twom64 = 0x1p-64L,
huge = 1.0e+4900L,
tiny = 1.0e-4900L;
long double
__scalblnl (long double x, long int n)
{
int32_t k,es,hx,lx;
GET_LDOUBLE_WORDS(es,hx,lx,x);
k = es&0x7fff; /* extract exponent */
if (__builtin_expect(k==0, 0)) { /* 0 or subnormal x */
if ((lx|(hx&0x7fffffff))==0) return x; /* +-0 */
x *= two63;
GET_LDOUBLE_EXP(es,x);
k = (es&0x7fff) - 63;
}
if (__builtin_expect(k==0x7fff, 0)) return x+x; /* NaN or Inf */
if (__builtin_expect(n< -50000, 0))
return tiny*__copysignl(tiny,x);
if (__builtin_expect(n> 50000 || k+n > 0x7ffe, 0))
return huge*__copysignl(huge,x); /* overflow */
/* Now k and n are bounded we know that k = k+n does not
overflow. */
k = k+n;
if (__builtin_expect(k > 0, 1)) /* normal result */
{SET_LDOUBLE_EXP(x,(es&0x8000)|k); return x;}
if (k <= -64)
return tiny*__copysignl(tiny,x); /*underflow*/
k += 64; /* subnormal result */
SET_LDOUBLE_EXP(x,(es&0x8000)|k);
return x*twom64;
}