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d8f1f2d9ab
So they can be checked with htl too.
67 lines
1.9 KiB
C
67 lines
1.9 KiB
C
/* Test pthread_cond_clockwait timeout.
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Copyright (C) 2019-2020 Free Software Foundation, Inc.
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This file is part of the GNU C Library.
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The GNU C Library is free software; you can redistribute it and/or
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modify it under the terms of the GNU Lesser General Public
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License as published by the Free Software Foundation; either
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version 2.1 of the License, or (at your option) any later version.
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The GNU C Library is distributed in the hope that it will be useful,
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but WITHOUT ANY WARRANTY; without even the implied warranty of
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MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
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Lesser General Public License for more details.
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You should have received a copy of the GNU Lesser General Public
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License along with the GNU C Library; if not, see
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<https://www.gnu.org/licenses/>. */
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#include <errno.h>
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#include <pthread.h>
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#include <stdio.h>
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#include <stdlib.h>
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#include <string.h>
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#include <time.h>
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#include <sys/time.h>
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#include <support/check.h>
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#include <support/timespec.h>
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#include <support/xthread.h>
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static pthread_mutex_t mut = PTHREAD_ERRORCHECK_MUTEX_INITIALIZER_NP;
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static pthread_cond_t cond = PTHREAD_COND_INITIALIZER;
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static int
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do_test_clock (clockid_t clockid)
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{
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/* Get the mutex. */
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xpthread_mutex_lock (&mut);
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/* Waiting for the condition will fail. But we want the timeout here. */
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const struct timespec ts_now = xclock_now (clockid);
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const struct timespec ts_timeout =
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timespec_add (ts_now, make_timespec (0, 500000000));
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/* In theory pthread_cond_clockwait could return zero here due to
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spurious wakeup. However that can't happen without a signal or an
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additional waiter. */
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TEST_COMPARE (pthread_cond_clockwait (&cond, &mut, clockid, &ts_timeout),
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ETIMEDOUT);
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xpthread_mutex_unlock (&mut);
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return 0;
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}
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static int
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do_test (void)
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{
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do_test_clock (CLOCK_MONOTONIC);
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do_test_clock (CLOCK_REALTIME);
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return 0;
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}
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#include <support/test-driver.c>
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