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202 lines
5.0 KiB
C
202 lines
5.0 KiB
C
/* Internal header for proving correct grouping in strings of numbers.
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Copyright (C) 1995,1996,1997,1998,2000,2003 Free Software Foundation, Inc.
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This file is part of the GNU C Library.
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Contributed by Ulrich Drepper <drepper@gnu.ai.mit.edu>, 1995.
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The GNU C Library is free software; you can redistribute it and/or
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modify it under the terms of the GNU Lesser General Public
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License as published by the Free Software Foundation; either
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version 2.1 of the License, or (at your option) any later version.
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The GNU C Library is distributed in the hope that it will be useful,
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but WITHOUT ANY WARRANTY; without even the implied warranty of
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MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
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Lesser General Public License for more details.
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You should have received a copy of the GNU Lesser General Public
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License along with the GNU C Library; if not, see
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<http://www.gnu.org/licenses/>. */
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#include <limits.h>
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#include <stddef.h>
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#include <string.h>
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#ifndef MAX
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#define MAX(a,b) ({ typeof(a) _a = (a); typeof(b) _b = (b); \
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_a > _b ? _a : _b; })
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#endif
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#ifdef USE_WIDE_CHAR
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# include <wctype.h>
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# define L_(Ch) L##Ch
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# define UCHAR_TYPE wint_t
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# define STRING_TYPE wchar_t
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#else
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# define L_(Ch) Ch
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# define UCHAR_TYPE unsigned char
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# define STRING_TYPE char
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#endif
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#include "grouping.h"
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/* Find the maximum prefix of the string between BEGIN and END which
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satisfies the grouping rules. It is assumed that at least one digit
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follows BEGIN directly. */
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const STRING_TYPE *
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#ifdef USE_WIDE_CHAR
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__correctly_grouped_prefixwc (const STRING_TYPE *begin, const STRING_TYPE *end,
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wchar_t thousands,
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#else
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__correctly_grouped_prefixmb (const STRING_TYPE *begin, const STRING_TYPE *end,
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const char *thousands,
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#endif
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const char *grouping)
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{
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#ifndef USE_WIDE_CHAR
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size_t thousands_len;
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int cnt;
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#endif
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if (grouping == NULL)
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return end;
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#ifndef USE_WIDE_CHAR
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thousands_len = strlen (thousands);
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#endif
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while (end > begin)
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{
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const STRING_TYPE *cp = end - 1;
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const char *gp = grouping;
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/* Check first group. */
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while (cp >= begin)
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{
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#ifdef USE_WIDE_CHAR
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if (*cp == thousands)
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break;
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#else
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if (cp[thousands_len - 1] == *thousands)
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{
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for (cnt = 1; thousands[cnt] != '\0'; ++cnt)
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if (thousands[cnt] != cp[thousands_len - 1 - cnt])
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break;
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if (thousands[cnt] == '\0')
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break;
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}
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#endif
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--cp;
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}
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/* We allow the representation to contain no grouping at all even if
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the locale specifies we can have grouping. */
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if (cp < begin)
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return end;
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if (end - cp == (int) *gp + 1)
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{
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/* This group matches the specification. */
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const STRING_TYPE *new_end;
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if (cp < begin)
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/* There is just one complete group. We are done. */
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return end;
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/* CP points to a thousands separator character. The preceding
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remainder of the string from BEGIN to NEW_END is the part we
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will consider if there is a grouping error in this trailing
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portion from CP to END. */
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new_end = cp - 1;
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/* Loop while the grouping is correct. */
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while (1)
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{
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/* Get the next grouping rule. */
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++gp;
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if (*gp == 0)
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/* If end is reached use last rule. */
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--gp;
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/* Skip the thousands separator. */
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--cp;
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if (*gp == CHAR_MAX
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#if CHAR_MIN < 0
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|| *gp < 0
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#endif
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)
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{
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/* No more thousands separators are allowed to follow. */
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while (cp >= begin)
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{
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#ifdef USE_WIDE_CHAR
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if (*cp == thousands)
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break;
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#else
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for (cnt = 0; thousands[cnt] != '\0'; ++cnt)
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if (thousands[cnt] != cp[thousands_len - cnt - 1])
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break;
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if (thousands[cnt] == '\0')
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break;
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#endif
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--cp;
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}
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if (cp < begin)
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/* OK, only digits followed. */
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return end;
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}
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else
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{
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/* Check the next group. */
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const STRING_TYPE *group_end = cp;
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while (cp >= begin)
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{
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#ifdef USE_WIDE_CHAR
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if (*cp == thousands)
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break;
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#else
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for (cnt = 0; thousands[cnt] != '\0'; ++cnt)
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if (thousands[cnt] != cp[thousands_len - cnt - 1])
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break;
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if (thousands[cnt] == '\0')
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break;
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#endif
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--cp;
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}
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if (cp < begin && group_end - cp <= (int) *gp)
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/* Final group is correct. */
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return end;
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if (cp < begin || group_end - cp != (int) *gp)
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/* Incorrect group. Punt. */
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break;
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}
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}
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/* The trailing portion of the string starting at NEW_END
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contains a grouping error. So we will look for a correctly
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grouped number in the preceding portion instead. */
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end = new_end;
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}
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else
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{
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/* Even the first group was wrong; determine maximum shift. */
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if (end - cp > (int) *gp + 1)
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end = cp + (int) *gp + 1;
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else if (cp < begin)
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/* This number does not fill the first group, but is correct. */
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return end;
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else
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/* CP points to a thousands separator character. */
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end = cp;
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}
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}
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return MAX (begin, end);
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}
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