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printoperation: fix another case where operation may complete twice
This is a little tricky. At first, I thought we had a codepath where we fail to schedule the idle that completes the print operation: if we take the gtk_print_backend_printer_list_is_done path for each printer backend, then printer_list_done_cb() is never executed and we never schedule the idle. But in fact, in this case, then backends == NULL at the bottom of find_printer(), and we'll schedule the idle there, so it's OK. Except it's not really OK, because we'll schedule it even if a printer was already found, resulting in the callback completing twice and a double free. Simplify this. Schedule the idle in find_printer() only if there are *initially* no backends, not also if all backends are immediately ready and already removed from consideration. Instead, always call printer_list_done_cb() for every backend in find_printer_init(). After the previous commit, printer_list_done_cb() will schedule the idle when appropriate. printer_list_done_cb() additionally disconnects signals that we did not connect in this codepath, but it does so using g_signal_handlers_disconnect_by_func, which is harmless. Otherwise, the only extra work it's doing is scheduling the idle, and that's exactly what find_printer_init() is missing.
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@ -1165,9 +1165,7 @@ find_printer_init (PrinterFinder *finder,
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if (gtk_print_backend_printer_list_is_done (backend))
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{
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finder->backends = g_list_remove (finder->backends, backend);
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gtk_print_backend_destroy (backend);
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g_object_unref (backend);
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printer_list_done_cb (backend, finder);
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}
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else
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{
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@ -1229,14 +1227,17 @@ find_printer (const char *printer,
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if (g_module_supported ())
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finder->backends = gtk_print_backend_load_modules ();
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if (finder->backends == NULL)
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{
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g_idle_add (find_printer_idle, finder);
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return;
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}
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for (node = finder->backends; !finder->found_printer && node != NULL; node = next)
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{
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next = node->next;
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find_printer_init (finder, GTK_PRINT_BACKEND (node->data));
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}
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if (finder->backends == NULL)
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g_idle_add (find_printer_idle, finder);
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}
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