Fix version number recognition heuristics
The regexp was wrong, for example it matched "2.20x" but failed to match "3.1". Some test cases: >>> def f(title): ... version_number = re.search(_version_number_re, title) ... if version_number: ... return not re.search(_incomplete_version_number_re, ... version_number.group(0)) ... else: ... return False ... >>> [(s, f(s.encode('ascii'))) for s in ['foo', 'foo 3', 'foo 3.', 'foo 3.1', 'foo 3.14', 'foo 3.2.1', 'foo 3.2.1alpha', 'foo 3.1.a', 'foo 3.a', 'foo 3.x.1']] [('foo', False), ('foo 3', False), ('foo 3.', False), ('foo 3.1', True), ('foo 3.14', True), ('foo 3.2.1', True), ('foo 3.2.1alpha', True), ('foo 3.1.a', False), ('foo 3.a', False), ('foo 3.x.1', False)]
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@ -84,9 +84,10 @@ class ChangeLog:
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return level, line[level:].strip()
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# Only accept dotted version numbers (e.g. "3.1", not "3").
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# Refuse ".x" in a version number: this indicates a version that is
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# not yet released.
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_version_number_re = re.compile(br'[0-9]\.[0-9][0-9.]+([^.]|\.[^0-9x])')
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# Refuse ".x" in a version number where x is a letter: this indicates
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# a version that is not yet released. Something like "3.1a" is accepted.
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_version_number_re = re.compile(br'[0-9]+\.[0-9A-Za-z.]+')
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_incomplete_version_number_re = re.compile(br'.*\.[A-Za-z]')
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def section_is_released_version(self, title):
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"""Whether this section is for a released version.
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@ -98,7 +99,11 @@ class ChangeLog:
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# that follows a particular pattern. These criteria may be revised
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# as needed in future versions of this script.
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version_number = re.search(self._version_number_re, title)
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return bool(version_number)
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if version_number:
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return not re.search(self._incomplete_version_number_re,
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version_number.group(0))
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else:
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return False
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def unreleased_version_title(self):
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"""The title to use if creating a new section for an unreleased version."""
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