don't align to sizes greater than than the allocation size
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b241910810
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0aec6d9302
@ -18,8 +18,9 @@ static void* mi_heap_malloc_zero_aligned_at(mi_heap_t* heap, size_t size, size_t
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// note: we don't require `size > offset`, we just guarantee that
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// note: we don't require `size > offset`, we just guarantee that
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// the address at offset is aligned regardless of the allocated size.
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// the address at offset is aligned regardless of the allocated size.
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mi_assert(alignment > 0 && alignment % sizeof(uintptr_t) == 0);
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mi_assert(alignment > 0 && alignment % sizeof(uintptr_t) == 0);
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if (alignment <= sizeof(uintptr_t)) return _mi_heap_malloc_zero(heap,size,zero);
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if (mi_unlikely(size > PTRDIFF_MAX)) return NULL; // we don't allocate more than PTRDIFF_MAX (see <https://sourceware.org/ml/libc-announce/2019/msg00001.html>)
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if (mi_unlikely(size > PTRDIFF_MAX)) return NULL; // we don't allocate more than PTRDIFF_MAX (see <https://sourceware.org/ml/libc-announce/2019/msg00001.html>)
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// note: we require that alignment is smaller than `size`
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if (mi_unlikely(alignment <= sizeof(uintptr_t) || alignment >= size)) return _mi_heap_malloc_zero(heap,size,zero);
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// try if there is a current small block with just the right alignment
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// try if there is a current small block with just the right alignment
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if (size <= MI_SMALL_SIZE_MAX) {
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if (size <= MI_SMALL_SIZE_MAX) {
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