be less aggressive in page reuse to reduce memory footprint
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@ -377,7 +377,7 @@ void _mi_page_retire(mi_page_t* page) {
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// is the only page left with free blocks. It is not clear
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// how to check this efficiently though... for now we just check
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// if its neighbours are almost fully used.
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if (mi_likely(page->block_size <= MI_LARGE_SIZE_MAX)) {
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if (mi_likely(page->block_size <= MI_SMALL_SIZE_MAX)) {
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if (mi_page_mostly_used(page->prev) && mi_page_mostly_used(page->next)) {
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return; // dont't retire after all
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}
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