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QDial: fix painting QDial when the rect has an offset

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When the QDial should be painted with an offset, the dial was not draw
correct.

Fixes: QTBUG-89574
Change-Id: I646c3d42fba34e8c603a8f81f363ed827f04d5de
Reviewed-by: Friedemann Kleint <Friedemann.Kleint@qt.io>
Reviewed-by: Richard Moe Gustavsen <richard.gustavsen@qt.io>
This commit is contained in:
Christian Ehrlicher 2020-12-22 15:43:13 +01:00
parent 180c662b07
commit 0ca3f1732a
2 changed files with 6 additions and 6 deletions
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4
src/widgets/styles/qcommonstyle.cpp
View File

@ -3230,8 +3230,8 @@ static StaticPolygonF<3> calcArrow(const QStyleOptionSlider *dial, qreal &a)
a = (Q_PI * 8 - (currentSliderPosition - dial->minimum) * 10 * Q_PI
/ (dial->maximum - dial->minimum)) / 6;
int xc = width / 2;
int yc = height / 2;
int xc = width / 2 + dial->rect.left();
int yc = height / 2 + dial->rect.top();
int len = r - QStyleHelper::calcBigLineSize(r) - 5;
if (len < 5)

8
src/widgets/styles/qstylehelper.cpp
View File

@ -181,7 +181,7 @@ static QPointF calcRadialPos(const QStyleOptionSlider *dial, qreal offset)
qreal len = r - QStyleHelper::calcBigLineSize(r) - 3;
qreal back = offset * len;
QPointF pos(QPointF(xc + back * qCos(a), yc - back * qSin(a)));
return pos;
return pos + dial->rect.topLeft();
}
qreal angle(const QPointF &p1, const QPointF &p2)
@ -254,7 +254,7 @@ QPolygonF calcLines(const QStyleOptionSlider *dial)
poly[2 * i + 1] = QPointF(xc + (r - 1) * c, yc -(r - 1) * s);
}
}
return poly;
return poly.translated(dial->rect.topLeft());
}
// This will draw a nice and shiny QDial for us. We don't want
@ -291,8 +291,8 @@ void drawDial(const QStyleOptionSlider *option, QPainter *painter)
p->setRenderHint(QPainter::Antialiasing);
const qreal d_ = r / 6;
const qreal dx = option->rect.x() + d_ + (width - 2 * r) / 2 + 1;
const qreal dy = option->rect.y() + d_ + (height - 2 * r) / 2 + 1;
const qreal dx = d_ + (width - 2 * r) / 2 + 1;
const qreal dy = d_ + (height - 2 * r) / 2 + 1;
QRectF br = QRectF(dx + 0.5, dy + 0.5,
int(r * 2 - 2 * d_ - 2),