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Inline Functor struct into FunctorCallable

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It's currently its only user, so drop the extra code and inheritance.

Change-Id: I6e525a9629b7289cc770133936e089683b763289
Reviewed-by: Thiago Macieira <thiago.macieira@intel.com>
This commit is contained in:
Mårten Nordheim 2023-07-05 16:38:32 +02:00
parent fd4319700f
commit 1bfdbe5c71
1 changed files with 6 additions and 9 deletions
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15
src/corelib/kernel/qobjectdefs_impl.h
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@ -332,21 +332,18 @@ namespace QtPrivate {
typedef decltype(std::declval<Functor>().operator()((std::declval<ArgList>())...)) Value;
};
template<typename Function, int N> struct Functor
{
template <typename SignalArgs, typename R>
static void call(Function &f, void *, void **arg) {
FunctorCall<typename Indexes<N>::Value, SignalArgs, R, Function>::call(f, arg);
}
};
template<typename Func, typename... Args>
struct FunctorCallable : Functor<Func, sizeof...(Args)>
struct FunctorCallable
{
using ReturnType = decltype(std::declval<Func>()(std::declval<Args>()...));
using Function = ReturnType(*)(Args...);
enum {ArgumentCount = sizeof...(Args)};
using Arguments = QtPrivate::List<Args...>;
template <typename SignalArgs, typename R>
static void call(Func &f, void *, void **arg) {
FunctorCall<typename Indexes<ArgumentCount>::Value, SignalArgs, R, Func>::call(f, arg);
}
};
template <typename Functor, typename... Args>