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Simplify QDate::weekNumber()

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Eliminate two local variables and don't even compute the year if we
don't need it.

Change-Id: If968c619750cead317641885a0fb9b9974954782
Reviewed-by: Andrei Golubev <andrei.golubev@qt.io>
Reviewed-by: Mårten Nordheim <marten.nordheim@qt.io>
This commit is contained in:
Edward Welbourne 2021-05-27 16:30:35 +02:00
parent c1ab14496a
commit ad554707dc
1 changed files with 5 additions and 7 deletions
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12
src/corelib/time/qdatetime.cpp
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@ -735,14 +735,12 @@ int QDate::weekNumber(int *yearNumber) const
// This could be replaced by use of QIso8601Calendar, once we implement it. // This could be replaced by use of QIso8601Calendar, once we implement it.
// The Thursday of the same week determines our answer: // The Thursday of the same week determines our answer:
QDate thursday(addDays(4 - dayOfWeek())); const QDate thursday(addDays(4 - dayOfWeek()));
int year = thursday.year();
// Week n's Thurs's DOY has 1 <= DOY - 7*(n-1) < 8, so 0 <= DOY + 6 - 7*n < 7:
int week = (thursday.dayOfYear() + 6) / 7;
if (yearNumber) if (yearNumber)
*yearNumber = year; *yearNumber = thursday.year();
return week;
// Week n's Thurs's DOY has 1 <= DOY - 7*(n-1) < 8, so 0 <= DOY + 6 - 7*n < 7:
return (thursday.dayOfYear() + 6) / 7;
} }
static bool inDateTimeRange(qint64 jd, bool start) static bool inDateTimeRange(qint64 jd, bool start)