46e4a9d523
Windows unhelpfully writes to only one byte of the output buffer when getsockopt is called for a boolean option. Therefore we have to zero initialise the int rather than initialising to -1 as was done before. This in general only works for little endian architecture, because the word would look like 0x01000000 on big endian. So I have added some compile time asserts in the assumption that windows is always little endian. This is ok for comparisons with 0/false, but not comparisons with true or nonzero values. In the case of IPV6_V6ONLY, it is documented as DWORD (unsigned int) but on some windows versions it is returned as a boolean triggering the warning. I removed the warning, as the conversion to int works on both LE and BE since it is only compared with zero. Task-number: QTBUG-23488 Change-Id: I3c586d1ada76465fc045a82661f289920c657a4c Reviewed-by: Richard J. Moore <rich@kde.org> Reviewed-by: Friedemann Kleint <Friedemann.Kleint@nokia.com> Reviewed-by: Andreas Holzammer <andreas.holzammer@kdab.com> |
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access | ||
bearer | ||
kernel | ||
socket | ||
ssl | ||
network.pro |