e4c6d73f92
QRect::center() should be defined for any QRect(x1,y1,x2,x2), INT_MIN <= x1, x2, y1, y2 <= INT_MAX because the average of two signed integers is always representable as a signed integer. But not when it's calculated as (x1+x2)/2, since that expression overflows when x1 > INT_MAX - x2. Instead of playing games with Hacker's Delight-style expressions, or use Google's patented algorithm, which requires two divisions, take advantage of the fact that int is not intmax_t and perform the calculation in the qint64 domain. The cast back to int is always well- defined since, as mentioned, the result is always representable in an int. Fix a test-case that expected a nonsensical result due to overflow. [ChangeLog][QtCore][QRect] Fixed integer overflow in center(). This fixes the result for some corner-cases like a 1x1 rectangle at (INT_MIN, INT_MIN), for which the previous implementation could return anything (due to invoking undefined behavior), but commonly returned (0, 0). Change-Id: I1a885ca6dff770327dd31655c3eb473fcfeb8878 Reviewed-by: Lars Knoll <lars.knoll@theqtcompany.com> |
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.gitignore | ||
qrect.pro | ||
tst_qrect.cpp |