bc98bba2f3
When variadic templates and decltype are supported, detect the best overload of operator() to call. Currently, the code takes the type of the operator(), which requires that the functor only has one, and that it has no template parameter. This feature is required if we want to connect to c++1y generic lambda (N3418) Change-Id: Ifa957da6955ea39ab804b58f320da9f98ff47d63 Reviewed-by: Jędrzej Nowacki <jedrzej.nowacki@digia.com> |
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signalbug | ||
test | ||
.gitignore | ||
qobject.pro | ||
tst_qobject.cpp |