1b972b210a
Escaping the '=' signs, otherwise awk fails on Solaris with awk: syntax error near line 1 awk: bailing out near line 1 Could not determine the target architecture! Build type: solaris-g++ (unknown, CPU features:) Change-Id: I201482395c0cec28c10853191032eaa0401f5beb Reviewed-by: Oswald Buddenhagen <oswald.buddenhagen@digia.com>
58 lines
1.5 KiB
Bash
Executable File
58 lines
1.5 KiB
Bash
Executable File
#!/bin/sh
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QMKSPEC=$1
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VERBOSE=$2
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SRCDIR=$3
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OUTDIR=$4
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RESULTFILE=$5
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TARGET=$6
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shift 6
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if [ "$TARGET" = "host" ]; then
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VARPREFIX="CFG_HOST"
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PROSUFFIX="_host"
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else
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VARPREFIX="CFG"
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PROSUFFIX=""
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fi
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LFLAGS="$SYSROOT_FLAG"
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CXXFLAGS="$SYSROOT_FLAG"
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# debuggery
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[ "$VERBOSE" = "yes" ] && echo "Determining architecture... ($*)"
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# build a test program but don't run it
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test -d "$OUTDIR/config.tests/arch" || mkdir -p "$OUTDIR/config.tests/arch"
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cd "$OUTDIR/config.tests/arch"
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[ -f Makefile ] && $MAKE distclean >/dev/null 2>&1
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OUTDIR=$OUTDIR "$OUTDIR/bin/qmake" -nocache -spec "$QMKSPEC" "QT_BUILD_TREE=$OUTDIR" "LIBS+=$LFLAGS" "QMAKE_CXXFLAGS+=$CXXFLAGS" "$SRCDIR/config.tests/arch/arch$PROSUFFIX.pro" >/dev/null 2>&1 || echo "qmake is broken" >&2
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ARCH=""
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[ "$VERBOSE" = "yes" ] && $MAKE || $MAKE >/dev/null 2>&1
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if [ -f ./arch.exe ]; then
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binary=./arch.exe
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elif [ -f ./arch ]; then
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binary=./arch
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elif [ -f ./libarch.so ]; then
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binary=./libarch.so
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else
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[ "$VERBOSE" = "yes" ] && echo "Unable to determine architecture!"
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exit 2
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fi
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if strings - $binary 2>/dev/null | \
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awk -F: '/\=\=Qt\=magic\=Qt\=\= Architecture/ { print "'$VARPREFIX'_ARCH=\"" $2 "\"" }
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/\=\=Qt\=magic\=Qt\=\= Sub-architecture/ { print "'$VARPREFIX'_CPUFEATURES=\"" $2 "\"" }' > "$RESULTFILE"
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then
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[ "$VERBOSE" = "yes" ] && echo " Found architecture in binary" && \
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cat "$RESULTFILE"
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else
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[ "$VERBOSE" = "yes" ] && echo "Unable to determine architecture!"
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exit 2
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fi
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$MAKE distclean >/dev/null 2>&1
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