stifle warning in tValue2Scalar()
Spun off from https://skia-review.googlesource.com/c/skia/+/242776. I was worried there that this indicated a bug, that we're actually working with a slightly-wrong denominator, but thanks to the wonders of float rounding, turns out everything's probably ok. This is the same as that CL above with unit tests that the important boundary conditions work correctly. Change-Id: I1df469daf48df12f0e72778e6af58f5e733452ed Reviewed-on: https://skia-review.googlesource.com/c/skia/+/242841 Reviewed-by: Mike Reed <reed@google.com> Commit-Queue: Mike Klein <mtklein@google.com>
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@ -13,12 +13,16 @@
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#define kMaxTValue 0x3FFFFFFF
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static inline SkScalar tValue2Scalar(int t) {
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constexpr static inline SkScalar tValue2Scalar(int t) {
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SkASSERT((unsigned)t <= kMaxTValue);
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const SkScalar kMaxTReciprocal = 1.0f / kMaxTValue;
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// 1/kMaxTValue can't be represented as a float, but it's close and the limits work fine.
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const SkScalar kMaxTReciprocal = 1.0f / (SkScalar)kMaxTValue;
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return t * kMaxTReciprocal;
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}
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static_assert(0.0f == tValue2Scalar( 0), "Lower limit should be exact.");
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static_assert(1.0f == tValue2Scalar(kMaxTValue), "Upper limit should be exact.");
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SkScalar SkContourMeasure::Segment::getScalarT() const {
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return tValue2Scalar(fTValue);
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}
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