skia2/experimental/Intersection/CubicUtilities.cpp
caryclark@google.com 9e49fb63d3 shape ops work in progress
add copyrights everywhere
start working on quadratic line segments (for quad intersection)

git-svn-id: http://skia.googlecode.com/svn/trunk@5286 2bbb7eff-a529-9590-31e7-b0007b416f81
2012-08-27 14:11:33 +00:00

155 lines
4.3 KiB
C++

/*
* Copyright 2012 Google Inc.
*
* Use of this source code is governed by a BSD-style license that can be
* found in the LICENSE file.
*/
#include "CubicUtilities.h"
#include "DataTypes.h"
#include "QuadraticUtilities.h"
void coefficients(const double* cubic, double& A, double& B, double& C, double& D) {
A = cubic[6]; // d
B = cubic[4] * 3; // 3*c
C = cubic[2] * 3; // 3*b
D = cubic[0]; // a
A -= D - C + B; // A = -a + 3*b - 3*c + d
B += 3 * D - 2 * C; // B = 3*a - 6*b + 3*c
C -= 3 * D; // C = -3*a + 3*b
}
// cubic roots
const double PI = 4 * atan(1);
static bool is_unit_interval(double x) {
return x > 0 && x < 1;
}
// from SkGeometry.cpp (and Numeric Solutions, 5.6)
int cubicRoots(double A, double B, double C, double D, double t[3]) {
if (approximately_zero(A)) { // we're just a quadratic
return quadraticRoots(B, C, D, t);
}
double a, b, c;
{
double invA = 1 / A;
a = B * invA;
b = C * invA;
c = D * invA;
}
double a2 = a * a;
double Q = (a2 - b * 3) / 9;
double R = (2 * a2 * a - 9 * a * b + 27 * c) / 54;
double Q3 = Q * Q * Q;
double R2MinusQ3 = R * R - Q3;
double adiv3 = a / 3;
double* roots = t;
double r;
if (R2MinusQ3 < 0) // we have 3 real roots
{
double theta = acos(R / sqrt(Q3));
double neg2RootQ = -2 * sqrt(Q);
r = neg2RootQ * cos(theta / 3) - adiv3;
if (is_unit_interval(r))
*roots++ = r;
r = neg2RootQ * cos((theta + 2 * PI) / 3) - adiv3;
if (is_unit_interval(r))
*roots++ = r;
r = neg2RootQ * cos((theta - 2 * PI) / 3) - adiv3;
if (is_unit_interval(r))
*roots++ = r;
}
else // we have 1 real root
{
double A = fabs(R) + sqrt(R2MinusQ3);
A = cube_root(A);
if (R > 0) {
A = -A;
}
if (A != 0) {
A += Q / A;
}
r = A - adiv3;
if (is_unit_interval(r))
*roots++ = r;
}
return (int)(roots - t);
}
// from http://www.cs.sunysb.edu/~qin/courses/geometry/4.pdf
// c(t) = a(1-t)^3 + 3bt(1-t)^2 + 3c(1-t)t^2 + dt^3
// c'(t) = -3a(1-t)^2 + 3b((1-t)^2 - 2t(1-t)) + 3c(2t(1-t) - t^2) + 3dt^2
// = 3(b-a)(1-t)^2 + 6(c-b)t(1-t) + 3(d-c)t^2
double derivativeAtT(const double* cubic, double t) {
double one_t = 1 - t;
double a = cubic[0];
double b = cubic[2];
double c = cubic[4];
double d = cubic[6];
return (b - a) * one_t * one_t + 2 * (c - b) * t * one_t + (d - c) * t * t;
}
// same as derivativeAtT
// which is more accurate? which is faster?
double derivativeAtT_2(const double* cubic, double t) {
double a = cubic[2] - cubic[0];
double b = cubic[4] - 2 * cubic[2] + cubic[0];
double c = cubic[6] + 3 * (cubic[2] - cubic[4]) - cubic[0];
return c * c * t * t + 2 * b * t + a;
}
void dxdy_at_t(const Cubic& cubic, double t, double& dx, double& dy) {
if (&dx) {
dx = derivativeAtT(&cubic[0].x, t);
}
if (&dy) {
dy = derivativeAtT(&cubic[0].y, t);
}
}
bool rotate(const Cubic& cubic, int zero, int index, Cubic& rotPath) {
double dy = cubic[index].y - cubic[zero].y;
double dx = cubic[index].x - cubic[zero].x;
if (approximately_equal(dy, 0)) {
if (approximately_equal(dx, 0)) {
return false;
}
memcpy(rotPath, cubic, sizeof(Cubic));
return true;
}
for (int index = 0; index < 4; ++index) {
rotPath[index].x = cubic[index].x * dx + cubic[index].y * dy;
rotPath[index].y = cubic[index].y * dx - cubic[index].x * dy;
}
return true;
}
double secondDerivativeAtT(const double* cubic, double t) {
double a = cubic[0];
double b = cubic[2];
double c = cubic[4];
double d = cubic[6];
return (c - 2 * b + a) * (1 - t) + (d - 2 * c + b) * t;
}
void xy_at_t(const Cubic& cubic, double t, double& x, double& y) {
double one_t = 1 - t;
double one_t2 = one_t * one_t;
double a = one_t2 * one_t;
double b = 3 * one_t2 * t;
double t2 = t * t;
double c = 3 * one_t * t2;
double d = t2 * t;
if (&x) {
x = a * cubic[0].x + b * cubic[1].x + c * cubic[2].x + d * cubic[3].x;
}
if (&y) {
y = a * cubic[0].y + b * cubic[1].y + c * cubic[2].y + d * cubic[3].y;
}
}