1b85323f10
Change-Id: I0647f641d4716af39f4afb832cfcc9fa7d571880 Reviewed-on: https://skia-review.googlesource.com/c/192832 Commit-Queue: Hal Canary <halcanary@google.com> Reviewed-by: Kevin Lubick <kjlubick@google.com> Reviewed-by: Ben Wagner <bungeman@google.com>
49 lines
1.3 KiB
Python
Executable File
49 lines
1.3 KiB
Python
Executable File
#!/usr/bin/env python
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# Copyright 2019 Google LLC.
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# Use of this source code is governed by a BSD-style license that can be
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# found in the LICENSE file.
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'''
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Generate a source file containing the given binary data.
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Output type is C++.
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'''
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import os
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import struct
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import sys
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import mmap
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def iterate_as_uint32(path):
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with open(path, 'rb') as f:
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s = struct.Struct('@I')
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assert s.size == 4
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mm = mmap.mmap(f.fileno(), 0, access=mmap.ACCESS_READ)
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assert (len(mm) % s.size) == 0
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for offset in xrange(0, len(mm), s.size):
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yield s.unpack_from(mm, offset)[0]
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mm.close()
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def convert(fmt, name, src_path, dst_path):
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header, line_begin, line_end, footer = fmt
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assert os.path.exists(src_path)
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src = iterate_as_uint32(src_path)
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with open(dst_path, 'w') as o:
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o.write(header.format(name))
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while True:
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line = ','.join('%d' % v for _, v in zip(range(8), src))
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if not line:
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break
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o.write('%s%s%s\n' % (line_begin, line, line_end))
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o.write(footer.format(name))
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cpp = ('#include <cstdint>\nextern "C" uint32_t {0}[] __attribute__((aligned(16))) = {{\n',
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'', ',', '}};\n')
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if __name__ == '__main__':
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print '\n'.join('>>> %r' % x for x in sys.argv)
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convert(cpp, sys.argv[1], sys.argv[2], sys.argv[3])
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