e2eac8b2fd
Motivation: those macros don't make any sense without the definitions in Test.h. BUG= R=mtklein@google.com Author: halcanary@google.com Review URL: https://codereview.chromium.org/138563004 git-svn-id: http://skia.googlecode.com/svn/trunk@13074 2bbb7eff-a529-9590-31e7-b0007b416f81
51 lines
1.7 KiB
C++
51 lines
1.7 KiB
C++
/*
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* Copyright 2012 Google Inc.
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*
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* Use of this source code is governed by a BSD-style license that can be
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* found in the LICENSE file.
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*/
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#include "SkDQuadImplicit.h"
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#include "SkPathOpsQuad.h"
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#include "Test.h"
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static bool point_on_parameterized_curve(const SkDQuad& quad, const SkDPoint& point) {
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SkDQuadImplicit q(quad);
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double xx = q.x2() * point.fX * point.fX;
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double xy = q.xy() * point.fX * point.fY;
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double yy = q.y2() * point.fY * point.fY;
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double x = q.x() * point.fX;
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double y = q.y() * point.fY;
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double c = q.c();
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double sum = xx + xy + yy + x + y + c;
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return approximately_zero(sum);
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}
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static const SkDQuad quadratics[] = {
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{{{0, 0}, {1, 0}, {1, 1}}},
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};
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static const size_t quadratics_count = SK_ARRAY_COUNT(quadratics);
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DEF_TEST(PathOpsQuadImplicit, reporter) {
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// split large quadratic
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// compare original, parts, to see if the are coincident
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for (size_t index = 0; index < quadratics_count; ++index) {
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const SkDQuad& test = quadratics[index];
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SkDQuadPair split = test.chopAt(0.5);
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SkDQuad midThird = test.subDivide(1.0/3, 2.0/3);
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const SkDQuad* quads[] = {
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&test, &midThird, &split.first(), &split.second()
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};
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size_t quadsCount = SK_ARRAY_COUNT(quads);
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for (size_t one = 0; one < quadsCount; ++one) {
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for (size_t two = 0; two < quadsCount; ++two) {
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for (size_t inner = 0; inner < 3; inner += 2) {
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REPORTER_ASSERT(reporter, point_on_parameterized_curve(*quads[one],
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(*quads[two])[inner]));
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}
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REPORTER_ASSERT(reporter, SkDQuadImplicit::Match(*quads[one], *quads[two]));
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}
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}
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}
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}
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