639e812d9f
In the majority of cases, a uniform is an equally good substitute, and replacing `sqrt(N)` with `unknownInput` actually makes the test clearer. Change-Id: I7bcb477571972d7aa2ce8c49b3674471f7310748 Bug: skia:12034 Reviewed-on: https://skia-review.googlesource.com/c/skia/+/411306 Auto-Submit: John Stiles <johnstiles@google.com> Commit-Queue: Ethan Nicholas <ethannicholas@google.com> Reviewed-by: Ethan Nicholas <ethannicholas@google.com>
81 lines
1.7 KiB
Plaintext
81 lines
1.7 KiB
Plaintext
uniform half4 colorRed, colorGreen;
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uniform half unknownInput;
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bool test() {
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int unknown = int(unknownInput);
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bool ok = true;
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int x = 32 + 2;
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ok = ok && (x == 34);
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x = 32 - 2;
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ok = ok && (x == 30);
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x = 32 * 2;
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ok = ok && (x == 64);
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x = 32 / 2;
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ok = ok && (x == 16);
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x = -1 == -1 ? 1 : -1;
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ok = ok && (x == 1);
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x = -1 == -2 ? 2 : -2;
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ok = ok && (x == -2);
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x = 0 != 1 ? 3 : -3;
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ok = ok && (x == 3);
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x = 0 != 0 ? 4 : -4;
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ok = ok && (x == -4);
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x = 6 > 5 ? 5 : -5;
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ok = ok && (x == 5);
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x = 6 > 6 ? 6 : -6;
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ok = ok && (x == -6);
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x = -1 < 0 ? 7 : -7;
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ok = ok && (x == 7);
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x = 1 < 0 ? 8 : -8;
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ok = ok && (x == -8);
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x = 6 >= 6 ? 9 : -9;
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ok = ok && (x == 9);
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x = 6 >= 7 ? 10 : -10;
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ok = ok && (x == -10);
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x = 6 <= 6 ? 11 : -11;
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ok = ok && (x == 11);
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x = 6 <= 5 ? 12 : -12;
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ok = ok && (x == -12);
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x = unknown + 0;
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ok = ok && (x == unknown);
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x = 0 + unknown;
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ok = ok && (x == unknown);
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x = unknown - 0;
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ok = ok && (x == unknown);
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x = unknown * 0;
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ok = ok && (x == 0);
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x = unknown * 1;
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ok = ok && (x == unknown);
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x = 1 * unknown;
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ok = ok && (x == unknown);
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x = 0 * unknown;
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ok = ok && (x == 0);
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x = unknown / 1;
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ok = ok && (x == unknown);
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x = 0 / unknown;
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ok = ok && (x == 0);
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x += 1;
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ok = ok && (x == 1);
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x += 0;
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ok = ok && (x == 1);
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x -= 2;
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ok = ok && (x == -1);
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x -= 0;
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ok = ok && (x == -1);
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x *= 1;
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ok = ok && (x == -1);
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x *= 2;
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ok = ok && (x == -2);
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x /= 1;
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ok = ok && (x == -2);
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x /= 2;
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ok = ok && (x == -1);
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return ok;
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}
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half4 main(float2 coords) {
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return test() ? colorGreen : colorRed;
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}
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