fa9a08369e
If we aren't wrapping the inlined function body in a loop, there's no need to add a scopeless Block; we've already got one. This doesn't affect the final output meaningfully--it just suppresses a newline--but it's one fewer IRNode allocation. Change-Id: Ib7b0014e908586d8acfcf6c23520873fad31d0b7 Reviewed-on: https://skia-review.googlesource.com/c/skia/+/345163 Commit-Queue: John Stiles <johnstiles@google.com> Reviewed-by: Brian Osman <brianosman@google.com> Auto-Submit: John Stiles <johnstiles@google.com>
82 lines
1.5 KiB
Metal
82 lines
1.5 KiB
Metal
#include <metal_stdlib>
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#include <simd/simd.h>
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using namespace metal;
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struct Inputs {
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};
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struct Outputs {
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float4 sk_FragColor [[color(0)]];
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};
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fragment Outputs fragmentMain(Inputs _in [[stage_in]], bool _frontFacing [[front_facing]], float4 _fragCoord [[position]]) {
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Outputs _outputStruct;
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thread Outputs* _out = &_outputStruct;
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float3 h3;
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h3 = float3(3.0);
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float4 h4;
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h4 = float4(4.0);
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h3.y = 1.0;
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h3.xz = float2(2.0);
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h4.zwxy = float4(4.0);
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_out->sk_FragColor = float4(1.0, 2.0, h3.x, h4.x);
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float2x2 h2x2;
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h2x2 = float2x2(2.0);
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float3x3 h3x3;
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h3x3 = float3x3(3.0);
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float4x4 h4x4;
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h4x4 = float4x4(4.0);
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h3x3[1] = float3(3.0);
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h4x4[3].w = 1.0;
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h2x2[0].x = 1.0;
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_out->sk_FragColor = float4(h2x2[0].x, h3x3[0].x, h4x4[0].x, 1.0);
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int2 i2;
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i2 = int2(2);
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int4 i4;
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i4 = int4(4);
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i4.xyz = int3(3);
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i2.y = 1;
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_out->sk_FragColor = float4(1.0, float(i2.x), 3.0, float(i4.x));
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float2 f2;
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f2 = float2(2.0);
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float3 f3;
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f3 = float3(3.0);
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f3.xy = float2(2.0);
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f2.x = 1.0;
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_out->sk_FragColor = float4(1.0, f2.x, f3.x, 4.0);
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float2x2 f2x2;
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f2x2 = float2x2(2.0);
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f2x2[0].x = 1.0;
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_out->sk_FragColor = float4(f2x2[0].x, float3x3(3.0)[0].x, float4x4(4.0)[0].x, 1.0);
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bool3 b3;
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b3 = bool3(true);
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bool4 b4;
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b4 = bool4(false);
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b4.xw = bool2(false);
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b3.z = true;
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_out->sk_FragColor = float4(1.0, bool(false) ? 1.0 : 0.0, b3.x ? 1.0 : 0.0, b4.x ? 1.0 : 0.0);
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return *_out;
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}
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