05c4bad470
git-svn-id: http://skia.googlecode.com/svn/trunk@7294 2bbb7eff-a529-9590-31e7-b0007b416f81
177 lines
6.0 KiB
C++
177 lines
6.0 KiB
C++
/*
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http://stackoverflow.com/questions/2009160/how-do-i-convert-the-2-control-points-of-a-cubic-curve-to-the-single-control-poi
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*/
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/*
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Let's call the control points of the cubic Q0..Q3 and the control points of the quadratic P0..P2.
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Then for degree elevation, the equations are:
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Q0 = P0
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Q1 = 1/3 P0 + 2/3 P1
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Q2 = 2/3 P1 + 1/3 P2
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Q3 = P2
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In your case you have Q0..Q3 and you're solving for P0..P2. There are two ways to compute P1 from
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the equations above:
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P1 = 3/2 Q1 - 1/2 Q0
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P1 = 3/2 Q2 - 1/2 Q3
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If this is a degree-elevated cubic, then both equations will give the same answer for P1. Since
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it's likely not, your best bet is to average them. So,
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P1 = -1/4 Q0 + 3/4 Q1 + 3/4 Q2 - 1/4 Q3
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Cubic defined by: P1/2 - anchor points, C1/C2 control points
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|x| is the euclidean norm of x
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mid-point approx of cubic: a quad that shares the same anchors with the cubic and has the
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control point at C = (3·C2 - P2 + 3·C1 - P1)/4
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Algorithm
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pick an absolute precision (prec)
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Compute the Tdiv as the root of (cubic) equation
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sqrt(3)/18 · |P2 - 3·C2 + 3·C1 - P1|/2 · Tdiv ^ 3 = prec
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if Tdiv < 0.5 divide the cubic at Tdiv. First segment [0..Tdiv] can be approximated with by a
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quadratic, with a defect less than prec, by the mid-point approximation.
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Repeat from step 2 with the second resulted segment (corresponding to 1-Tdiv)
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0.5<=Tdiv<1 - simply divide the cubic in two. The two halves can be approximated by the mid-point
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approximation
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Tdiv>=1 - the entire cubic can be approximated by the mid-point approximation
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confirmed by (maybe stolen from)
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http://www.caffeineowl.com/graphics/2d/vectorial/cubic2quad01.html
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// maybe in turn derived from http://www.cccg.ca/proceedings/2004/36.pdf
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// also stored at http://www.cis.usouthal.edu/~hain/general/Publications/Bezier/bezier%20cccg04%20paper.pdf
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*/
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#include "CubicUtilities.h"
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#include "CurveIntersection.h"
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#include "LineIntersection.h"
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const bool AVERAGE_END_POINTS = true; // results in better fitting curves
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#define USE_CUBIC_END_POINTS 1
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static double calcTDiv(const Cubic& cubic, double precision, double start) {
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const double adjust = sqrt(3) / 36;
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Cubic sub;
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const Cubic* cPtr;
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if (start == 0) {
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cPtr = &cubic;
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} else {
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// OPTIMIZE: special-case half-split ?
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sub_divide(cubic, start, 1, sub);
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cPtr = ⊂
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}
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const Cubic& c = *cPtr;
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double dx = c[3].x - 3 * (c[2].x - c[1].x) - c[0].x;
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double dy = c[3].y - 3 * (c[2].y - c[1].y) - c[0].y;
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double dist = sqrt(dx * dx + dy * dy);
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double tDiv3 = precision / (adjust * dist);
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double t = cube_root(tDiv3);
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if (start > 0) {
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t = start + (1 - start) * t;
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}
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return t;
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}
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void demote_cubic_to_quad(const Cubic& cubic, Quadratic& quad) {
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quad[0] = cubic[0];
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if (AVERAGE_END_POINTS) {
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const _Point fromC1 = { (3 * cubic[1].x - cubic[0].x) / 2, (3 * cubic[1].y - cubic[0].y) / 2 };
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const _Point fromC2 = { (3 * cubic[2].x - cubic[3].x) / 2, (3 * cubic[2].y - cubic[3].y) / 2 };
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quad[1].x = (fromC1.x + fromC2.x) / 2;
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quad[1].y = (fromC1.y + fromC2.y) / 2;
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} else {
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lineIntersect((const _Line&) cubic[0], (const _Line&) cubic[2], quad[1]);
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}
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quad[2] = cubic[3];
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}
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int cubic_to_quadratics(const Cubic& cubic, double precision, SkTDArray<Quadratic>& quadratics) {
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SkTDArray<double> ts;
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cubic_to_quadratics(cubic, precision, ts);
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int tsCount = ts.count();
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double t1Start = 0;
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int order = 0;
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for (int idx = 0; idx <= tsCount; ++idx) {
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double t1 = idx < tsCount ? ts[idx] : 1;
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Cubic part;
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sub_divide(cubic, t1Start, t1, part);
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Quadratic q1;
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demote_cubic_to_quad(part, q1);
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Quadratic s1;
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int o1 = reduceOrder(q1, s1);
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if (order < o1) {
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order = o1;
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}
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memcpy(quadratics.append(), o1 < 2 ? s1 : q1, sizeof(Quadratic));
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t1Start = t1;
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}
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return order;
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}
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static bool addSimpleTs(const Cubic& cubic, double precision, SkTDArray<double>& ts) {
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double tDiv = calcTDiv(cubic, precision, 0);
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if (tDiv >= 1) {
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return true;
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}
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if (tDiv >= 0.5) {
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*ts.append() = 0.5;
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return true;
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}
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return false;
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}
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static void addTs(const Cubic& cubic, double precision, double start, double end,
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SkTDArray<double>& ts) {
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double tDiv = calcTDiv(cubic, precision, 0);
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double parts = ceil(1.0 / tDiv);
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for (double index = 0; index < parts; ++index) {
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double newT = start + (index / parts) * (end - start);
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if (newT > 0 && newT < 1) {
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*ts.append() = newT;
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}
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}
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}
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// flavor that returns T values only, deferring computing the quads until they are needed
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// FIXME: when called from recursive intersect 2, this could take the original cubic
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// and do a more precise job when calling chop at and sub divide by computing the fractional ts.
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// it would still take the prechopped cubic for reduce order and find cubic inflections
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void cubic_to_quadratics(const Cubic& cubic, double precision, SkTDArray<double>& ts) {
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Cubic reduced;
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int order = reduceOrder(cubic, reduced, kReduceOrder_QuadraticsAllowed);
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if (order < 3) {
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return;
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}
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double inflectT[2];
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int inflections = find_cubic_inflections(cubic, inflectT);
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SkASSERT(inflections <= 2);
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if (inflections == 0 && addSimpleTs(cubic, precision, ts)) {
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return;
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}
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if (inflections == 1) {
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CubicPair pair;
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chop_at(cubic, pair, inflectT[0]);
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addTs(pair.first(), precision, 0, inflectT[0], ts);
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addTs(pair.second(), precision, inflectT[0], 1, ts);
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return;
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}
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if (inflections == 2) {
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if (inflectT[0] > inflectT[1]) {
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SkTSwap(inflectT[0], inflectT[1]);
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}
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Cubic part;
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sub_divide(cubic, 0, inflectT[0], part);
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addTs(part, precision, 0, inflectT[0], ts);
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sub_divide(cubic, inflectT[0], inflectT[1], part);
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addTs(part, precision, inflectT[0], inflectT[1], ts);
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sub_divide(cubic, inflectT[1], 1, part);
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addTs(part, precision, inflectT[1], 1, ts);
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return;
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}
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addTs(cubic, precision, 0, 1, ts);
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}
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