skia2/tools/retrieve_from_googlesource.py
Ravi Mistry e5be65e998 Update references to master branch
Change-Id: I1bfd1b655af6cdfbd64452b1e594a276425095fe
Bug: skia:11987
Docs-Preview: https://skia.org/?cl=410790
Reviewed-on: https://skia-review.googlesource.com/c/skia/+/410790
Reviewed-by: Eric Boren <borenet@google.com>
Commit-Queue: Ravi Mistry <rmistry@google.com>
2021-05-21 15:18:16 +00:00

38 lines
996 B
Python
Executable File

#!/usr/bin/python
# Copyright (c) 2014 The Chromium Authors. All rights reserved.
# Use of this source code is governed by a BSD-style license that can be
# found in the LICENSE file.
"""Retrieve the given file from googlesource.com."""
from contextlib import closing
import base64
import sys
import urllib2
def get(repo_url, filepath):
"""Retrieve the contents of the given file from the given googlesource repo.
Args:
repo_url: string; URL of the repository from which to retrieve the file.
filepath: string; path of the file within the repository.
Return:
string; the contents of the given file.
"""
base64_url = '/'.join((repo_url, '+', 'main', filepath)) + '?format=TEXT'
with closing(urllib2.urlopen(base64_url)) as f:
return base64.b64decode(f.read())
if __name__ == '__main__':
if len(sys.argv) != 3:
print >> sys.stderr, 'Usage: %s <repo_url> <filepath>' % sys.argv[0]
sys.exit(1)
sys.stdout.write(get(sys.argv[1], sys.argv[2]))