Fix bug in parser that allows "(foo):42" as a labeled statement.

Fixes issue 918.

Review URL: http://codereview.chromium.org/5044003

git-svn-id: http://v8.googlecode.com/svn/branches/bleeding_edge@5830 ce2b1a6d-e550-0410-aec6-3dcde31c8c00
This commit is contained in:
lrn@chromium.org 2010-11-16 12:10:48 +00:00
parent 1341dde85f
commit 0464b33625
2 changed files with 37 additions and 2 deletions

View File

@ -1692,11 +1692,13 @@ Statement* Parser::ParseExpressionOrLabelledStatement(ZoneStringList* labels,
// ExpressionStatement | LabelledStatement ::
// Expression ';'
// Identifier ':' Statement
bool starts_with_idenfifier = (peek() == Token::IDENTIFIER);
Expression* expr = ParseExpression(true, CHECK_OK);
if (peek() == Token::COLON && expr &&
if (peek() == Token::COLON && starts_with_idenfifier && expr &&
expr->AsVariableProxy() != NULL &&
!expr->AsVariableProxy()->is_this()) {
// Expression is a single identifier, and not, e.g., a parenthesized
// identifier.
VariableProxy* var = expr->AsVariableProxy();
Handle<String> label = var->name();
// TODO(1240780): We don't check for redeclaration of labels

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@ -0,0 +1,33 @@
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// Parser should not accept parentheses around labels.
// See http://code.google.com/p/v8/issues/detail?id=918
// The label was parsed as an expression and then tested for being a
// single identifier. This threw away the parentheses.
assertThrows("(label):42;");