Minor bug in int32 TypeRecordingBinaryOpStub.
BUG=none TEST=none Patch by Rodolph Perfetta from ARM Ltd. Review URL: http://codereview.chromium.org/6612017 git-svn-id: http://v8.googlecode.com/svn/branches/bleeding_edge@7055 ce2b1a6d-e550-0410-aec6-3dcde31c8c00
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@ -872,12 +872,11 @@ void FloatingPointHelper::DoubleIs32BitInteger(MacroAssembler* masm,
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// Exponent greater than 31 cannot yield 32-bit integers.
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// Also, a positive value with an exponent equal to 31 is outside of the
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// signed 32-bit integer range.
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__ tst(src1, Operand(HeapNumber::kSignMask));
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__ cmp(scratch, Operand(30), eq); // Executed for positive. If exponent is 30
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// the gt condition will be "correct" and
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// the next instruction will be skipped.
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__ cmp(scratch, Operand(31), ne); // Executed for negative and positive where
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// exponent is not 30.
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// Another way to put it is that if (exponent - signbit) > 30 then the
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// number cannot be represented as an int32.
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Register tmp = dst;
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__ sub(tmp, scratch, Operand(src1, LSR, 31));
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__ cmp(tmp, Operand(30));
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__ b(gt, not_int32);
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// - Bits [21:0] in the mantissa are not null.
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__ tst(src2, Operand(0x3fffff));
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