Improve modulo operation in lithium on IA32.
Implement fast paths for the special cases like PowerOfTwo divisors and the dividend being smaller than the divisor (non-negative). BUG=v8:1314 Review URL: http://codereview.chromium.org//6816049 git-svn-id: http://v8.googlecode.com/svn/branches/bleeding_edge@7704 ce2b1a6d-e550-0410-aec6-3dcde31c8c00
This commit is contained in:
parent
34d1ea45d7
commit
37f33a7087
1
AUTHORS
1
AUTHORS
@ -39,4 +39,5 @@ Ryan Dahl <coldredlemur@gmail.com>
|
||||
Sanjoy Das <sanjoy@playingwithpointers.com>
|
||||
Subrato K De <subratokde@codeaurora.org>
|
||||
Vlad Burlik <vladbph@gmail.com>
|
||||
Yuqiang Xian <yuqiang.xian@intel.com>
|
||||
Zaheer Ahmad <zahmad@codeaurora.org>
|
||||
|
@ -799,20 +799,61 @@ void LCodeGen::DoModI(LModI* instr) {
|
||||
__ and_(dividend, divisor - 1);
|
||||
__ bind(&done);
|
||||
} else {
|
||||
LOperand* right = instr->InputAt(1);
|
||||
ASSERT(ToRegister(instr->InputAt(0)).is(eax));
|
||||
ASSERT(ToRegister(instr->result()).is(edx));
|
||||
NearLabel done, remainder_eq_dividend, slow, do_subtraction, both_positive;
|
||||
Register left_reg = ToRegister(instr->InputAt(0));
|
||||
Register right_reg = ToRegister(instr->InputAt(1));
|
||||
Register result_reg = ToRegister(instr->result());
|
||||
|
||||
Register right_reg = ToRegister(right);
|
||||
ASSERT(left_reg.is(eax));
|
||||
ASSERT(result_reg.is(edx));
|
||||
ASSERT(!right_reg.is(eax));
|
||||
ASSERT(!right_reg.is(edx));
|
||||
|
||||
// Check for x % 0.
|
||||
if (instr->hydrogen()->CheckFlag(HValue::kCanBeDivByZero)) {
|
||||
__ test(right_reg, ToOperand(right));
|
||||
__ test(right_reg, Operand(right_reg));
|
||||
DeoptimizeIf(zero, instr->environment());
|
||||
}
|
||||
|
||||
__ test(left_reg, Operand(left_reg));
|
||||
__ j(zero, &remainder_eq_dividend);
|
||||
__ j(sign, &slow);
|
||||
|
||||
__ test(right_reg, Operand(right_reg));
|
||||
__ j(not_sign, &both_positive);
|
||||
// The sign of the divisor doesn't matter.
|
||||
__ neg(right_reg);
|
||||
|
||||
__ bind(&both_positive);
|
||||
// If the dividend is smaller than the nonnegative
|
||||
// divisor, the dividend is the result.
|
||||
__ cmp(left_reg, Operand(right_reg));
|
||||
__ j(less, &remainder_eq_dividend);
|
||||
|
||||
// Check if the divisor is a PowerOfTwo integer.
|
||||
Register scratch = ToRegister(instr->TempAt(0));
|
||||
__ mov(scratch, right_reg);
|
||||
__ sub(Operand(scratch), Immediate(1));
|
||||
__ test(scratch, Operand(right_reg));
|
||||
__ j(not_zero, &do_subtraction);
|
||||
__ and_(left_reg, Operand(scratch));
|
||||
__ jmp(&remainder_eq_dividend);
|
||||
|
||||
__ bind(&do_subtraction);
|
||||
const int kUnfolds = 3;
|
||||
// Try a few subtractions of the dividend.
|
||||
__ mov(scratch, left_reg);
|
||||
for (int i = 0; i < kUnfolds; i++) {
|
||||
// Reduce the dividend by the divisor.
|
||||
__ sub(left_reg, Operand(right_reg));
|
||||
// Check if the dividend is less than the divisor.
|
||||
__ cmp(left_reg, Operand(right_reg));
|
||||
__ j(less, &remainder_eq_dividend);
|
||||
}
|
||||
__ mov(left_reg, scratch);
|
||||
|
||||
// Slow case, using idiv instruction.
|
||||
__ bind(&slow);
|
||||
// Sign extend to edx.
|
||||
__ cdq();
|
||||
|
||||
@ -820,12 +861,12 @@ void LCodeGen::DoModI(LModI* instr) {
|
||||
if (instr->hydrogen()->CheckFlag(HValue::kBailoutOnMinusZero)) {
|
||||
NearLabel positive_left;
|
||||
NearLabel done;
|
||||
__ test(eax, Operand(eax));
|
||||
__ test(left_reg, Operand(left_reg));
|
||||
__ j(not_sign, &positive_left);
|
||||
__ idiv(right_reg);
|
||||
|
||||
// Test the remainder for 0, because then the result would be -0.
|
||||
__ test(edx, Operand(edx));
|
||||
__ test(result_reg, Operand(result_reg));
|
||||
__ j(not_zero, &done);
|
||||
|
||||
DeoptimizeIf(no_condition, instr->environment());
|
||||
@ -835,6 +876,12 @@ void LCodeGen::DoModI(LModI* instr) {
|
||||
} else {
|
||||
__ idiv(right_reg);
|
||||
}
|
||||
__ jmp(&done);
|
||||
|
||||
__ bind(&remainder_eq_dividend);
|
||||
__ mov(result_reg, left_reg);
|
||||
|
||||
__ bind(&done);
|
||||
}
|
||||
}
|
||||
|
||||
|
Loading…
Reference in New Issue
Block a user