Improve modulo operation in lithium on IA32.

Implement fast paths for the special cases like PowerOfTwo divisors
and the dividend being smaller than the divisor (non-negative).

BUG=v8:1314

Review URL: http://codereview.chromium.org//6816049

git-svn-id: http://v8.googlecode.com/svn/branches/bleeding_edge@7704 ce2b1a6d-e550-0410-aec6-3dcde31c8c00
This commit is contained in:
sgjesse@chromium.org 2011-04-28 14:58:45 +00:00
parent 34d1ea45d7
commit 37f33a7087
2 changed files with 55 additions and 7 deletions

View File

@ -39,4 +39,5 @@ Ryan Dahl <coldredlemur@gmail.com>
Sanjoy Das <sanjoy@playingwithpointers.com>
Subrato K De <subratokde@codeaurora.org>
Vlad Burlik <vladbph@gmail.com>
Yuqiang Xian <yuqiang.xian@intel.com>
Zaheer Ahmad <zahmad@codeaurora.org>

View File

@ -799,20 +799,61 @@ void LCodeGen::DoModI(LModI* instr) {
__ and_(dividend, divisor - 1);
__ bind(&done);
} else {
LOperand* right = instr->InputAt(1);
ASSERT(ToRegister(instr->InputAt(0)).is(eax));
ASSERT(ToRegister(instr->result()).is(edx));
NearLabel done, remainder_eq_dividend, slow, do_subtraction, both_positive;
Register left_reg = ToRegister(instr->InputAt(0));
Register right_reg = ToRegister(instr->InputAt(1));
Register result_reg = ToRegister(instr->result());
Register right_reg = ToRegister(right);
ASSERT(left_reg.is(eax));
ASSERT(result_reg.is(edx));
ASSERT(!right_reg.is(eax));
ASSERT(!right_reg.is(edx));
// Check for x % 0.
if (instr->hydrogen()->CheckFlag(HValue::kCanBeDivByZero)) {
__ test(right_reg, ToOperand(right));
__ test(right_reg, Operand(right_reg));
DeoptimizeIf(zero, instr->environment());
}
__ test(left_reg, Operand(left_reg));
__ j(zero, &remainder_eq_dividend);
__ j(sign, &slow);
__ test(right_reg, Operand(right_reg));
__ j(not_sign, &both_positive);
// The sign of the divisor doesn't matter.
__ neg(right_reg);
__ bind(&both_positive);
// If the dividend is smaller than the nonnegative
// divisor, the dividend is the result.
__ cmp(left_reg, Operand(right_reg));
__ j(less, &remainder_eq_dividend);
// Check if the divisor is a PowerOfTwo integer.
Register scratch = ToRegister(instr->TempAt(0));
__ mov(scratch, right_reg);
__ sub(Operand(scratch), Immediate(1));
__ test(scratch, Operand(right_reg));
__ j(not_zero, &do_subtraction);
__ and_(left_reg, Operand(scratch));
__ jmp(&remainder_eq_dividend);
__ bind(&do_subtraction);
const int kUnfolds = 3;
// Try a few subtractions of the dividend.
__ mov(scratch, left_reg);
for (int i = 0; i < kUnfolds; i++) {
// Reduce the dividend by the divisor.
__ sub(left_reg, Operand(right_reg));
// Check if the dividend is less than the divisor.
__ cmp(left_reg, Operand(right_reg));
__ j(less, &remainder_eq_dividend);
}
__ mov(left_reg, scratch);
// Slow case, using idiv instruction.
__ bind(&slow);
// Sign extend to edx.
__ cdq();
@ -820,12 +861,12 @@ void LCodeGen::DoModI(LModI* instr) {
if (instr->hydrogen()->CheckFlag(HValue::kBailoutOnMinusZero)) {
NearLabel positive_left;
NearLabel done;
__ test(eax, Operand(eax));
__ test(left_reg, Operand(left_reg));
__ j(not_sign, &positive_left);
__ idiv(right_reg);
// Test the remainder for 0, because then the result would be -0.
__ test(edx, Operand(edx));
__ test(result_reg, Operand(result_reg));
__ j(not_zero, &done);
DeoptimizeIf(no_condition, instr->environment());
@ -835,6 +876,12 @@ void LCodeGen::DoModI(LModI* instr) {
} else {
__ idiv(right_reg);
}
__ jmp(&done);
__ bind(&remainder_eq_dividend);
__ mov(result_reg, left_reg);
__ bind(&done);
}
}