Do not transform a/b into a * (1/b) in the parser for integer constants.
Strength reduction should be performed at a later stage. This change avoid going to a double representation the case of integer division. Review URL: http://codereview.chromium.org/6044010 git-svn-id: http://v8.googlecode.com/svn/branches/bleeding_edge@6174 ce2b1a6d-e550-0410-aec6-3dcde31c8c00
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@ -2323,26 +2323,6 @@ Expression* Parser::ParseBinaryExpression(int prec, bool accept_IN, bool* ok) {
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}
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}
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// Convert constant divisions to multiplications for speed.
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if (op == Token::DIV &&
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y && y->AsLiteral() && y->AsLiteral()->handle()->IsNumber()) {
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double y_val = y->AsLiteral()->handle()->Number();
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int64_t y_int = static_cast<int64_t>(y_val);
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// There are rounding issues with this optimization, but they don't
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// apply if the number to be divided with has a reciprocal that can be
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// precisely represented as a floating point number. This is the case
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// if the number is an integer power of 2. Negative integer powers of
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// 2 work too, but for -2, -1, 1 and 2 we don't do the strength
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// reduction because the inlined optimistic idiv has a reasonable
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// chance of succeeding by producing a Smi answer with no remainder.
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if (static_cast<double>(y_int) == y_val &&
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(IsPowerOf2(y_int) || IsPowerOf2(-y_int)) &&
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(y_int > 2 || y_int < -2)) {
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y = NewNumberLiteral(1 / y_val);
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op = Token::MUL;
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}
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}
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// For now we distinguish between comparisons and other binary
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// operations. (We could combine the two and get rid of this
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// code and AST node eventually.)
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