83f778aff1
This fixes the logic in the desugaring of destructuring assignments. In particular, a spread element would not check if previous `next` results had already been done, and would always call `next()` again. Change-Id: I1bd384678722e6cf51c5777fc3b0dd965360291a Reviewed-on: https://chromium-review.googlesource.com/c/v8/v8/+/2430488 Commit-Queue: Gus Caplan <snek@chromium.org> Reviewed-by: Leszek Swirski <leszeks@chromium.org> Cr-Commit-Position: refs/heads/master@{#70144}
27 lines
483 B
JavaScript
27 lines
483 B
JavaScript
// Copyright 2020 the V8 project authors. All rights reserved.
|
|
// Use of this source code is governed by a BSD-style license that can be
|
|
// found in the LICENSE file.
|
|
|
|
'use strict';
|
|
|
|
let called = 0
|
|
const it = {
|
|
[Symbol.iterator]() {
|
|
return this;
|
|
},
|
|
next() {
|
|
called += 1;
|
|
return {
|
|
value: 42,
|
|
done: true,
|
|
};
|
|
},
|
|
};
|
|
|
|
const [a, b, ...c] = it;
|
|
|
|
assertEquals(called, 1);
|
|
assertEquals(a, undefined);
|
|
assertEquals(b, undefined);
|
|
assertEquals(c.length, 0);
|