v8/test/intl/regress-9912.js
Frank Tang e64fa14fa0 Fix the format of date range older than Oct 15 1582
Bug: v8:9912
Change-Id: Ib9deba176f7aaa2ffca2db811c5273af673028ca
Reviewed-on: https://chromium-review.googlesource.com/c/v8/v8/+/1884955
Reviewed-by: Jakob Kummerow <jkummerow@chromium.org>
Commit-Queue: Frank Tang <ftang@chromium.org>
Cr-Commit-Position: refs/heads/master@{#64621}
2019-10-29 18:12:25 +00:00

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// Copyright 2019 the V8 project authors. All rights reserved.
// Use of this source code is governed by a BSD-style license that can be
// found in the LICENSE file.
let df = new Intl.DateTimeFormat("en");
// A modern date
let d1 = new Date(2019, 3, 4);
let d2 = new Date(2019, 4, 5);
assertEquals(df.format(d1), df.formatRange(d1, d1));
assertEquals(df.format(d2), df.formatRange(d2, d2));
assertEquals("4/4/2019 5/5/2019", df.formatRange(d1, d2));
// An old date just before the Julian / Gregorian switch
let d3 = new Date(1582, 8, 13);
let d4 = new Date(1582, 9, 14);
assertEquals(df.format(d3), df.formatRange(d3, d3));
assertEquals(df.format(d4), df.formatRange(d4, d4));
assertEquals("9/13/1582 10/14/1582", df.formatRange(d3, d4));
// An older date
let d5 = new Date(1000, 0, 1);
let d6 = new Date(1001, 1, 2);
assertEquals(df.format(d5), df.formatRange(d5, d5));
assertEquals(df.format(d6), df.formatRange(d6, d6));
assertEquals("1/1/1000 2/2/1001", df.formatRange(d5, d6));