v8/test/mjsunit/regress/regress-1273677.js
Leszek Swirski a858cfd3ec [interpreter] Don't emit dead try blocks
Try blocks (whether catch or finally) will unconditionally create
handler tables and start a new basic block for the exception handler.
This can accidentally resurrect a dead block when the entire try block
is dead (and hence can never enter the exception handler in the first
place).

Add a deadness check to BuildTryCatch/Finally to fix this.

Bug: chromium:1273677
Change-Id: Icda9deb1459e47de5cb83e7b636299e24c3ebe77
Reviewed-on: https://chromium-review.googlesource.com/c/v8/v8/+/3306555
Commit-Queue: Leszek Swirski <leszeks@chromium.org>
Commit-Queue: Marja Hölttä <marja@chromium.org>
Reviewed-by: Marja Hölttä <marja@chromium.org>
Auto-Submit: Leszek Swirski <leszeks@chromium.org>
Cr-Commit-Position: refs/heads/main@{#78179}
2021-12-01 10:44:09 +00:00

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JavaScript

// Copyright 2021 the V8 project authors. All rights reserved.
// Use of this source code is governed by a BSD-style license that can be
// found in the LICENSE file.
//
// Flags: --allow-natives-syntax
function test() {}
function foo() {
// --test() will throw a ReferenceError, making the rest of the for-of loop
// dead. The destructuring assignment is still part of the same expression,
// and it generates a try-finally for its iteration, so if it isn't fully
// eliminated the finally block may resurrect the destructuring assignment
// loop.
for (let [x] of --test()) {}
}
%PrepareFunctionForOptimization(foo);
try { foo() } catch {}
%OptimizeFunctionOnNextCall(foo);
try { foo() } catch {}