2814885477
The spec requires that a null @@split / @@replace symbol is treated exactly the same as if it were undefined, i.e. execution should move on to the default implementation instead of throwing a TypeError. BUG=v8:6313 Review-Url: https://codereview.chromium.org/2845153002 Cr-Commit-Position: refs/heads/master@{#44959}
23 lines
828 B
JavaScript
23 lines
828 B
JavaScript
// Copyright 2015 the V8 project authors. All rights reserved.
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// Use of this source code is governed by a BSD-style license that can be
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// found in the LICENSE file.
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var pattern = {toString: () => ""};
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var limit = { value: 3 };
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pattern[Symbol.split] = function(string, limit) {
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return string.length * limit.value;
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};
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// Check object coercible fails.
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assertThrows(() => String.prototype.split.call(null, pattern, limit),
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TypeError);
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// Override is called.
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assertEquals(15, "abcde".split(pattern, limit));
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// Non-callable override.
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pattern[Symbol.split] = "dumdidum";
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assertThrows(() => "abcde".split(pattern, limit), TypeError);
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// Null override.
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pattern[Symbol.split] = null;
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assertEquals(["a", "b", "c", "d", "e"], "abcde".split(pattern));
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assertEquals("[Symbol.split]", RegExp.prototype[Symbol.split].name);
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