2814885477
The spec requires that a null @@split / @@replace symbol is treated exactly the same as if it were undefined, i.e. execution should move on to the default implementation instead of throwing a TypeError. BUG=v8:6313 Review-Url: https://codereview.chromium.org/2845153002 Cr-Commit-Position: refs/heads/master@{#44959}
22 lines
780 B
JavaScript
22 lines
780 B
JavaScript
// Copyright 2015 the V8 project authors. All rights reserved.
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// Use of this source code is governed by a BSD-style license that can be
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// found in the LICENSE file.
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var pattern = {
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[Symbol.replace]: (string, newValue) => string + newValue,
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toString: () => "c"
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};
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// Check object coercible fails.
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assertThrows(() => String.prototype.replace.call(null, pattern, "x"),
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TypeError);
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// Override is called.
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assertEquals("abcdex", "abcde".replace(pattern, "x"));
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// Non-callable override.
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pattern[Symbol.replace] = "dumdidum";
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assertThrows(() => "abcde".replace(pattern, "x"), TypeError);
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// Null override.
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pattern[Symbol.replace] = null;
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assertEquals("abXde", "abcde".replace(pattern, "X"));
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assertEquals("[Symbol.replace]", RegExp.prototype[Symbol.replace].name);
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