8b165d414f
When with or catch is nested inside finally, we were not properly restoring the context in the stack for the finally code. Also, as a small optimization, restore it from the handler block instead of iteratively unwinding contexts. R=fschneider@chromium.org BUG= TEST= Review URL: http://codereview.chromium.org/7837023 git-svn-id: http://v8.googlecode.com/svn/branches/bleeding_edge@9160 ce2b1a6d-e550-0410-aec6-3dcde31c8c00
43 lines
1.8 KiB
JavaScript
43 lines
1.8 KiB
JavaScript
// Copyright 2011 the V8 project authors. All rights reserved.
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// Redistribution and use in source and binary forms, with or without
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// modification, are permitted provided that the following conditions are
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// met:
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//
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// * Redistributions of source code must retain the above copyright
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// notice, this list of conditions and the following disclaimer.
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// * Redistributions in binary form must reproduce the above
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// copyright notice, this list of conditions and the following
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// disclaimer in the documentation and/or other materials provided
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// with the distribution.
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// * Neither the name of Google Inc. nor the names of its
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// contributors may be used to endorse or promote products derived
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// from this software without specific prior written permission.
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//
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// THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS
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// "AS IS" AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT
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// LIMITED TO, THE IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR
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// A PARTICULAR PURPOSE ARE DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT
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// OWNER OR CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL,
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// SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT
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// LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE,
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// DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY
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// THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT
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// (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE
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// OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.
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function Test() {
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var left = 'XXX';
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var right = 'YYY';
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for (var i = 0; i < 3; i++) {
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var cons = left + right;
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var substring = cons.substring(2, 4);
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try {
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with ({Test: i})
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continue;
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} finally { }
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}
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return substring;
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}
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assertEquals('XY', Test());
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