.. | ||
build.generic.cmd | ||
build.VS2010.cmd | ||
build.VS2012.cmd | ||
build.VS2013.cmd | ||
build.VS2015.cmd | ||
README.md |
Command line scripts for Visual Studio compilation without IDE
Here are a few command lines for reference :
Build with Visual Studio 2013 for msvcr120.dll
Running the following command will build both the Release Win32
and Release x64
versions:
build\build.VS2013.cmd
The result of each build will be in the corresponding build\bin\Release\{ARCH}\
folder.
If you want to only need one architecture:
- Win32:
build\build.generic.cmd VS2013 Win32 Release v120
- x64:
build\build.generic.cmd VS2013 x64 Release v120
If you want a Debug build:
- Win32:
build\build.generic.cmd VS2013 Win32 Debug v120
- x64:
build\build.generic.cmd VS2013 x64 Debug v120
Build with Visual Studio 2015 for msvcr140.dll
Running the following command will build both the Release Win32
and Release x64
versions:
build\build.VS2015.cmd
The result of each build will be in the corresponding build\bin\Release\{ARCH}\
folder.
If you want to only need one architecture:
- Win32:
build\build.generic.cmd VS2015 Win32 Release v140
- x64:
build\build.generic.cmd VS2015 x64 Release v140
If you want a Debug build:
- Win32:
build\build.generic.cmd VS2015 Win32 Debug v140
- x64:
build\build.generic.cmd VS2015 x64 Debug v140
Build with Visual Studio 2015 for msvcr120.dll
You need to invoke build\build.generic.cmd
with the proper arguments:
For Win32
build\build.generic.cmd VS2015 Win32 Release v120
The result of the build will be in the build\bin\Release\Win32\
folder.
For x64
build\build.generic.cmd VS2015 x64 Release v120
The result of the build will be in the build\bin\Release\x64\
folder.
If you want Debug builds, replace Release
with Debug
.