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706688aaef
This patch fixes bugs in ldbl-128ibm frexpl for 32-bit systems shown up by warnings: ../sysdeps/ieee754/ldbl-128ibm/s_frexpl.c:82:4: warning: left shift count >= width of type ../sysdeps/ieee754/ldbl-128ibm/s_frexpl.c:129:5: warning: left shift count >= width of type This did in fact show up in test-ldouble.out (alongside all the other problems there ... maybe we should again consider running the libm tests at finer granularity from the makefiles) as already covered by the testsuite after the previous patch that fixed these bugs for 64-bit systems. The fix is simply using 1LL instead of 1L when shifting by 52. Tested for powerpc32 (soft float). [BZ #16619] [BZ #16740] * sysdeps/ieee754/ldbl-128ibm/s_frexpl.c (__frexpl): Use 1LL << 52 instead of 1L << 52.
149 lines
3.6 KiB
C
149 lines
3.6 KiB
C
/* s_frexpl.c -- long double version of s_frexp.c.
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* Conversion to IEEE quad long double by Jakub Jelinek, jj@ultra.linux.cz.
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*/
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/*
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* ====================================================
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* Copyright (C) 1993 by Sun Microsystems, Inc. All rights reserved.
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*
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* Developed at SunPro, a Sun Microsystems, Inc. business.
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* Permission to use, copy, modify, and distribute this
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* software is freely granted, provided that this notice
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* is preserved.
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* ====================================================
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*/
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#if defined(LIBM_SCCS) && !defined(lint)
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static char rcsid[] = "$NetBSD: $";
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#endif
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/*
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* for non-zero x
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* x = frexpl(arg,&exp);
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* return a long double fp quantity x such that 0.5 <= |x| <1.0
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* and the corresponding binary exponent "exp". That is
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* arg = x*2^exp.
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* If arg is inf, 0.0, or NaN, then frexpl(arg,&exp) returns arg
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* with *exp=0.
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*/
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#include <math.h>
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#include <math_private.h>
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#include <math_ldbl_opt.h>
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long double __frexpl(long double x, int *eptr)
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{
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uint64_t hx, lx, ix, ixl;
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int64_t explo, expon;
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double xhi, xlo;
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ldbl_unpack (x, &xhi, &xlo);
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EXTRACT_WORDS64 (hx, xhi);
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EXTRACT_WORDS64 (lx, xlo);
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ixl = 0x7fffffffffffffffULL & lx;
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ix = 0x7fffffffffffffffULL & hx;
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expon = 0;
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if (ix >= 0x7ff0000000000000ULL || ix == 0)
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{
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/* 0,inf,nan. */
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*eptr = expon;
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return x;
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}
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expon = ix >> 52;
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if (expon == 0)
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{
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/* Denormal high double, the low double must be 0.0. */
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int cnt;
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/* Normalize. */
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if (sizeof (ix) == sizeof (long))
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cnt = __builtin_clzl (ix);
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else if ((ix >> 32) != 0)
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cnt = __builtin_clzl ((long) (ix >> 32));
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else
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cnt = __builtin_clzl ((long) ix) + 32;
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cnt = cnt - 12;
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expon -= cnt;
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ix <<= cnt + 1;
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}
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expon -= 1022;
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ix &= 0x000fffffffffffffULL;
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hx &= 0x8000000000000000ULL;
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hx |= (1022LL << 52) | ix;
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if (ixl != 0)
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{
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/* If the high double is an exact power of two and the low
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double has the opposite sign, then the exponent calculated
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from the high double is one too big. */
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if (ix == 0
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&& (int64_t) (hx ^ lx) < 0)
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{
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hx += 1LL << 52;
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expon -= 1;
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}
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explo = ixl >> 52;
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if (explo == 0)
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{
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/* The low double started out as a denormal. Normalize its
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mantissa and adjust the exponent. */
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int cnt;
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if (sizeof (ixl) == sizeof (long))
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cnt = __builtin_clzl (ixl);
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else if ((ixl >> 32) != 0)
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cnt = __builtin_clzl ((long) (ixl >> 32));
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else
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cnt = __builtin_clzl ((long) ixl) + 32;
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cnt = cnt - 12;
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explo -= cnt;
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ixl <<= cnt + 1;
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}
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/* With variable precision we can't assume much about the
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magnitude of the returned low double. It may even be a
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denormal. */
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explo -= expon;
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ixl &= 0x000fffffffffffffULL;
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lx &= 0x8000000000000000ULL;
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if (explo <= 0)
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{
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/* Handle denormal low double. */
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if (explo > -52)
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{
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ixl |= 1LL << 52;
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ixl >>= 1 - explo;
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}
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else
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{
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ixl = 0;
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lx = 0;
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if ((hx & 0x7ff0000000000000ULL) == (1023LL << 52))
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{
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/* Oops, the adjustment we made above for values a
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little smaller than powers of two turned out to
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be wrong since the returned low double will be
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zero. This can happen if the input was
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something weird like 0x1p1000 - 0x1p-1000. */
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hx -= 1LL << 52;
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expon += 1;
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}
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}
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explo = 0;
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}
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lx |= (explo << 52) | ixl;
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}
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INSERT_WORDS64 (xhi, hx);
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INSERT_WORDS64 (xlo, lx);
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x = ldbl_pack (xhi, xlo);
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*eptr = expon;
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return x;
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}
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#if IS_IN (libm)
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long_double_symbol (libm, __frexpl, frexpl);
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#else
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long_double_symbol (libc, __frexpl, frexpl);
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#endif
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