Formal parameters of an arrow function are parsed even if the function
itself is preparsed. It is because we don't know if it is an arrow
function parameter list or just comma separated expression list.
When we parse:
(a, b = (function c() { return a; })())
call to function c may be just part of an assignment in an expression
list, but if it's followed by:
=> { return b; }
It is an arrow function and the call to c is a default parameter.
Before we see the arrow we might have already created a parse task
to parse function c.
BUG=v8:6093
Change-Id: I59a59acfdbbfd808dab1518060748be2addcd54a
Reviewed-on: https://chromium-review.googlesource.com/493347
Commit-Queue: Wiktor Garbacz <wiktorg@google.com>
Reviewed-by: Marja Hölttä <marja@chromium.org>
Reviewed-by: Daniel Vogelheim <vogelheim@chromium.org>
Cr-Commit-Position: refs/heads/master@{#45132}
9a572e1d5f